All categories

2 years ago

My friend Elentine purchased 9 Naxvips for $2 each and some toys for $8 each.

Mathematics

1 answer:

Andrew [12]2 years ago

5 0

The equations to model the relationship between Elentine's naxvips (x) and toys (y) is: Total cost = 18 + 8y

<em><u>Solution:</u></em>

Let "x" be the number of naxvips bought

Let "y" be the number of toys bought

From given,

Cost of each naxvip = $ 2

Cost of each toy = $ 8

My friend Elentine purchased 9 Naxvips for $2 each and some toys for $8 each.

Thus according to given we frame a equation as:

Total cost = 9 naxvips x 2 + y x 8

$Total\ cost = 9 \times 2 + y \times 8\\\\Total\ cost = 18+8y$

Thus total cost spend is (18 + 8y) dollars

You might be interested in

What is the answer to this in degrees

sasho [114]

Answer:

155

Step-by-step explanation:

As the diagram shows, it looks the same as the other side. In, that case it would be the same so 155.

4 0

3 years ago

Read 2 more answers

Jawan made a table to figure out how much he eearns at his job.

Ilya [14]

Lovely let’s do the cha cha side

6 0

2 years ago

Read 2 more answers

Can someone help me with this one

Viktor [21]

Answer:

y = -4x + (-2)

Step-by-step explanation:

if you plug in the x values in the equation it equals y

4 0

3 years ago

Consider f and c below. f(x, y) = x2 i + y2 j c is the arc of the parabola y = 2x2 from (−1, 2) to (1, 2) (a) find a function f

Korvikt [17]

If there is some scalar function $f(x,y)$ such that

$\nabla f(x,y)=\mathbf f(x,y)=x^2\,\mathbf i+y^2\,\mathbf j$

then we want to find $f$ such that

$\dfrac{\partial f}{\partial x}=x^2\implies f(x,y)=\dfrac{x^3}3+g(y)$
$\dfrac{\partial f}{\partial y}=y^2=\dfrac{\mathrm dg}{\mathrm dy}\implies g(y)=\dfrac{y^3}3+C$
$\implies f(x,y)=\dfrac{x^3}3+\dfrac{y^3}3+C$

So the vector field $\mathbf f(x,y)$ is conservative, which means the fundamental theorem applies; the line integral of $\mathbf f$ along any path $\mathcal C$ parameterized by some vector-valued function $\mathbf r(t)$ over $a\le t\le b$ is given by

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=a}^{t=b}\mathbf f(\mathbf r(t))\cdot\dfrac{\mathrm d\mathbf r}{\mathrm dt}\,\mathrm dt=f(\mathbf r(b))-f(\mathbf r(a))$

In this case,

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f(1,2)-f(-1,2)=\dfrac23$

5 0

2 years ago

You work in the state of Nebraska where the sales tax is five and a half percent what would be the tax rate expressed as a decim

dedylja [7]

Just answered this lol

3 0

2 years ago