Hello
1 km = 1000 m
12 km = 12,000 m
Each day, she runs 10 * 400 m = 4000 m
12,000 m / 4000 m = 3
It will take 3 days.
Have a nice day
The expected length of code for one encoded symbol is
where 
is the probability of picking the letter 
, and 
is the length of code needed to encode . is given to us, and we have
so that we expect a contribution of
bits to the code per encoded letter. For a string of length 
, we would then expect ![E[L]=1.375n](https://tex.z-dn.net/?f=E%5BL%5D%3D1.375n)
.
By definition of variance, we have
![\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3DE%5Cleft%5B%28L-E%5BL%5D%29%5E2%5Cright%5D%3DE%5BL%5E2%5D-E%5BL%5D%5E2)
For a string consisting of one letter, we have
so that the variance for the length such a string is
"squared" bits per encoded letter. For a string of length , we would get ![\mathrm{Var}[L]=1.859n](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3D1.859n)
.
Answer:
6 shirts
Step-by-step explanation:
The cost of a shirt and 2 ties is ...
$18.50 +2(7.50) = $33.50
For $205, Frank can buy $205/$33.50 = 6.12 sets of shirt and ties.
Frank can buy 6 shirts (and 12 ties) for an amount less than $205.
_____
<em>Additional comment</em>
Frank's cost will be $201 for that purchase.
The GCF of the first two is 4p³q².The GCF of the second two is 8pq⁵.The GCF of the third two is 4p²q⁵.The GCF of the fourth two is 8p²q.The GCF of the fifth two is 4p²q.
To find the GCF of each pair, find the greatest number that will divide into each coefficient. As for the variable portions, choose the variable that has the smallest exponent from each pair.
