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vova2212 [387]
4 years ago
10

Use the diagram to answer the question

Mathematics
1 answer:
nadya68 [22]4 years ago
7 0

Step-by-step explanation:

sin A =  \frac{BC}{AC}     \\  \\  \therefore \: sin A =  \frac{13}{15}  \\  \\ \therefore \: sin A =  0.866 \\  \\ \therefore \: sin A =  sin \: 60 \degree \\  \\ \therefore \:  A =  \: 60 \degree \\  \\

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What is 372 rounded to the nearest 100
Xelga [282]
372

The number 3 is in the hundreds place.

Look to the number immediately to the right.

We know that 7 is bigger than 3.

So, we add 1 to 3 and the rest become 0.

Answer: 400
7 0
3 years ago
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At the start of his race, 86-kg Olympic 100m champion Usain Bolt pushes against the starting block, exerting an average force of
Leviafan [203]
1) Determine the horizontal force, Fx, exerted by the block on Usain

cos(20°) = Fx / F => Fx = F*cos(20) = 1700N*cos(20) = 1597.48 N

2) Determine the Impulse of that force on Usain.

I = F*t = 1597.48N * 0.32s = 511.19 N*s

3) Determine change in momentum of Usain, Δp

Δp = I = 511.19 N*s

4) Find change if velocity

Δp = Δ(mV) = mΔV => ΔV = Δp / m = 511.19 N*s / 86 kg = 5.94 m/s

Given the Usain started from rest, the velocity is ΔV - 0 = 5.94 m/s

Answer: 5.94 m/s
3 0
4 years ago
HELP PLEASE LOOK AT PICTURE
solniwko [45]

Answer:

It decreases.

Step-by-step explanation:

10 / d

Lets say that it was 10 / 40, which is 10 divided by 40, 0.25.

Now, it has increased to twice the amount of that.

1 / 80, 10 divided by 80, which is 0.125

So, it decreases.

4 0
4 years ago
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Please help <br> answer asap
ss7ja [257]
Do u still need the answer to this problem its been 2 weeks now!!
3 0
4 years ago
5. Select All equations that have a solution of 2"
Pachacha [2.7K]

Answer:

none of these have a solution of 2.

Step-by-step explanation:

4x+ 15 = 27

x=3

x + 6 =3

x = 3

2(x+5)=18

x = 4

x + 9 = 6

x = -3

if my understanding of what the equations are supposed to be please let me know what they are supposed to be, because with the way they are typed it is hard to tell :)

6 0
3 years ago
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