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4 years ago

Movement of a stationary object

1 answer:

5 0

I would say that you're describing an impossible situation.
If the object is stationary, then it has no movement.
If the object has movement, then it's not stationary.

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A 6.5 kg rock thrown down from a 120m high cliff with initial velocity 18 m/s down. Calculate

uranmaximum [27]

Answer:

fast. i have spoken

Explanation:

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3 years ago

Smaller mammals use proportionately more energy than larger mammals; that is, it takes more energy per gram to power a mouse tha

timama [110]

Answer:

10,200 Cal. per day

Explanation:

The mouse consumes 3.0 Cal each day, and has a mass of 20 grams. We can use this data to obtain a ratio of energy consumption per mass

$\frac{3.0 \ Cal}{20 g} = 0.15 \frac{Cal}{g}$ .

For the human, we need to convert the 68 kilograms to grams. We can do this with a conversion factor. We know that:

$1 \ kg = 1000 \ g$ ,

Now, we can divide by 1 kg on each side

$\frac{1 \ kg}{1 \ kg} = \frac{1000 \ g}{1 \ kg}$ ,

$1 = \frac{1000 \ g}{1 \ kg}$ .

Using this conversion factor, we can obtain the mass of the human in grams, instead of kilograms. First, lets take:

$mass_{human} = 68 \ kg$

We can multiply this mass for the conversion factor, we are allowed to do this, cause the conversion factor equals 1, and its adimensional

$mass_{human} = 68 \ kg * \frac{1000 \ g}{1 \ kg}$

$mass_{human} = 68,000 g$

Now that we know the mass of the human on grams, we can multiply for our ratio of energy consumption

$68,000 \ g * 0.15 \frac{Cal}{g} = 10,200 \ Cal$

So, we would need 10,200 Cal per day.

3 0

3 years ago

Choose the pair of elements that will most likely have the least ionic character.

Alinara [238K]

I think the answer is c h and o

3 0

3 years ago

Read 2 more answers

A closed container is filled with oxygen. The pressure in the container is 245 kPa . What is the pressure in millimeters of merc

Makovka662 [10]

Answer:

Answer to the question is: 1837.65 millimeters of mercury are equal to 245 kPa.

Explanation:

1 kPa are equal to 7.50062 millimeters of mercury.

6 0

3 years ago

If you travel from Yakima to Ellensburg (Yakima to Ellensburg is 50 miles) with a speed of 60 miles/hour for half of the

koban [17]

Answer:

$\displaystyle \frac{480}{7}\approx 68.6\; \rm mph$ .

Explanation:

The average speed of an object is equal to total distance over total time.

Distance traveled: $\rm 50 \; mi$ .

How much time is taken? This trip is divided into two halves, each of distance $\displaystyle \frac{50}{2} = 25\;\rm mi$ .

Time spent on the first half of the trip:

$\displaystyle t_1 = \frac{s_1}{v_1} = \frac{25}{60} = \frac{5}{12}\; \rm hours$ .

Similarly, time spent on the second half of the trip:

$\displaystyle t_2 = \frac{s_2}{v_2} = \frac{25}{80} = \frac{5}{16}\; \rm hours$ .

In total:

$\displaystyle \frac{5}{12} + \frac{5}{16} = \frac{35}{48} \; \rm hours$ .

Average speed:

$\begin{aligned} \text{Average speed} &= \frac{\text{Total Distance}}{\text{Total Time}}\\ &= 50 \left/\frac{35}{48}\right.\\ &= 50 \cdot \frac{48}{35} \\&= \frac{480}{7}\approx 68.6\; \rm mph \end{aligned}$ .

This value turned out to be slightly different from the average of the speed during the two halves of the journey. The reason is that the object traveled at each speed for a different amount of time. It spent more time at the slower speed, which gives that speed a greater weight in the average. That explains why the average speed is closer to $\rm 60\; mph$ rather than $\rm 80\; mph$ .

3 0

3 years ago