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3 years ago

What work is done when a person pushes a refrigerator across the floor 12m using 480N of force ?

Physics

1 answer:

KiRa [710]3 years ago

6 0

Answer:

W = 5760 J

Explanation:

Force (F) = 480 N
Distance (d) = 12 m
Work (W) = ?

Use the formula:

W = F * d

Replace with the data, and solve:

W = 480 N * 12 m
W = 5760 J

The work done was 5760 Joules.

Greetings.

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Explain an example of how energy is transferred from one form to another

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Answer:

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Chemical Energy is converted to Electrical Energy (stove)

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3 years ago

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3 years ago

What is an atom called after it was proven wrong

skad [1K]

Answer:

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3 years ago

You are playing ice hockey with friends on a frozen pond. The hockey puck (mass 0.2 kg) is sliding on the ice at 10 m/s when it

chubhunter [2.5K]

Answer:

The mass of the hailstone is $m_2 = 0.05$

Explanation:

From the question we are told that

The mass of the hockey puck is $m_1 = 0.2 \ kg$

The initial speed of the puck is $u_1 = 10 \ m/s$

The final speed of the puck is $v_f = 8 \ m/s$

According to the principles of linear momentum

$m_1u_1 + m_2u_2 = (m_1 + m_2)v_f$

At initial the velocity of the hailstone was zero so

$u_2 = 0 \ m/s$

$m_1 u_1 = (m_1 + m_2 )v_f$

substituting values

$0.2 * 10 = (0.2 + m_2 )* 8$

=> $2 = (0.2 + m_2 )* 8$

=> $0.25 = 0.2 + m_2$

=> $m_2 = 0.05$

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3 years ago

Ignoring any effects of dc resistance, what is the total reactance of a 250 mH coil in series with a 4.7 microfarad capacitor at

Paha777 [63]

The total reactance of the inductor and the capacitor is 470.1 ohms.

The given parameters;

inductance of the coil, L = 250 mH
capacitance, C = 4.7 μ
frequency of the circuit, f = 60 Hz

The inductive reactance of the coil is calculated as follows;

$X_l = \omega L\\\\X_l = 2\pi f L\\\\X_l = 2\pi \times 60 \times 250 \times 10^{-3}\\\\X_l = 94.26 \ ohms$

The capacitive reactance of the capacitor is calculated as follows;

$X_c = \frac{1}{\omega C} \\\\X_c = \frac{1}{2\pi f C} \\\\X_c = \frac{1}{2\pi \times 60 \times 4.7 \times 10^{-6}} \\\\X_c = 564.31 \ ohms$

The impedance of the circuit is calculated as follows;

$Z = \sqrt{(X_c - X_l)^2} \\\\Z = X_c - X_l\\\\Z = 564.31 - 94.26\\\\Z = 470.1 \ ohms$

Thus, the total reactance of the inductor and the capacitor is 470.1 ohms.

Learn more here:brainly.com/question/10886711

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2 years ago