I believe the correct answer from the choices listed above is the first option. Decreasing a telescope's eyepiece focal length will increase magnification. <span>The magnification of the </span>telescope<span> image is (</span>focal length<span> of the objective) divided by (</span>focal length <span>of the </span>eyepiece<span>). Hope this answers the question.</span>
Answer:
The distance covered is 40 m and the displacement is 31,6m.
Explanation:
The distance covered is the sum of the two distances (10+30). The displacement is equal to the distance of the hipotenusa of the triangle that the two distances (10 m to north and 30m to east) create. Using the Pythagoras theorem the displacent is equal to the Square root of (30^2 +10^2) .
Power = work/time = (Force times distance)/time
= (30N *10.0m)/5.00s = 300/5 = 60 Watts
Answer:
Explanation:
Radius = 9.5 x 10⁻² m
area of circle = 3.14 x (9.5 x 10⁻² )²
A = 283.38 x 10⁻⁴ m²
magnetic moment = area x current
M = 283.38 x 10⁻⁴ x 5
= 1416.9 x 10⁻⁴ Am²
Torque = MBsinθ
M is magnetic moment , B is magnetic field .
Max torque = 1416.9 x 10⁻⁴ x 3.4 x 10⁻³ , for θ = 90
= 4817.46 x 10⁻⁷
= 481.7 x 10⁻⁶
= 481.7 μ J
Energy = - MBcosθ
Max energy when θ = 180
MB = 4817.46 x 10⁻⁷ J
Min energy = - 4817.46 x 10⁻⁷ for θ = 0
Answer:
Inertia
Explanation:
The state of motion of an object is defined by its velocity the speed with a direction. Thus, inertia could be redefined as follows: Inertia: tendency of an object to resist changes in its velocity - and ( in the absence of an unbalanced force ) will remain with a zero velocity.