The answer is C! Have a great day!
Well, it depends on the school. Do you have a list of the classes?
Answer:
a. (x^3+8)(x^2-4)
b. x=1 and x=1/2
Step-by-step explanation:
a. (x^3+8)(x^2-4) = x^5-4x^3+8x^2-32 [foil method: first,outside,inside,last]
b. use quadratic formula: -b +/- square root b^2-4ac / 2a
2=a; -3=b; 1=c
-(-3) + square root (-3)^2 - 4(2)(1) / 2(2)
3 + 1 / 4 = 4/4 = 1
3 - 1/4 = 2/4 = 1/2
Answer:
y = ½(13- x)
Step-by-step explanation:
Step 1. Find the<em> slope (m₁) of the original line
</em>
The equation for the original line is
y = 2x - 6
slope = m₁ = 2
Step 2. Find the <em>slope (m₂) of the perpendicular line
</em>
m₂ = -1/m₁ Substitute the value of m₁
m₂ = -1/2
Step 3. Find the <em>equation for the perpendicular line</em>
y = mx + b Substitute the value of m₂
y = -½x + b
The line passes through (5, 4).
4 = -½(5) + b Add 5/2 to each side
4 = -5/2 + b Add 2 to each side
b = 13/2
y = -½x + 13/2
y = ½(13 – x)
In the image, below, the red line is the graph of your original equation.
The blue line passing through (5, 4) is the perpendicular line.
9514 1404 393
Answer:
$12,720
Step-by-step explanation:
The amount is given by the formula ...
A = P(1 +rt)
where P is the principal, invested at rate r for t years.
A = $12,000(1 +0.06·1) = $12,720
The total amount after 1 year is $12,720.