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3 years ago

7 hundreds × 10 in unit form

1 answer:

6 0

All you got to do is put your mind to this, if its hundreds you convert into a number with 2 zeros, so 700, then multiply it by ten by just adding a zero

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MATH <br> can somebody help me with these questions?

Dmitriy789 [7]

I’m learning this in class as well
Ok so basically you just need to find 2 random points so like (30,100) and (20,30)
And my question for you is do you know the equation format?

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3 years ago

shelby made 5 qt of juice for a picnic. She said that she made 1 1/4 cups of juice cups of juice. Explain shelby's mistake

Alexandra [31]

I don't know either she is not quite

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4 years ago

Is 6 a factor of 42x + 30y

zhuklara [117]

I think so yes!!!!!!!!!!!!!!

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3 years ago

A man walked steadily from 11 am to 2.30 pm at 5 kilometres per hour how far did he walk!

matrenka [14]

Answer:

Distance traveled 17.5 kilometers

Step-by-step explanation:

We can use the following equation to find the distance traveled,

Distance traveled = Speed * Time

First we need to find the total time he walked = 2.30 p.m. - 11.a.m.

= $3.5$ hours

Now we can substitute the values to the equation,

Distance traveled = $5$ kilometers per hour * $3.5$ hours

= $5*3.5$ kilometers

= 17.5 kilometers

3 0

3 years ago

within a kiambu county,students were randomly assigned to one of two mathematics teachers.Mrs.Elite and Mrs. Bright. After the a

DerKrebs [107]

Using the t-distribution, as we have the standard deviation for the samples, it is found that since the absolute value of the test statistic is greater than the critical value, we reject the claim that Mrs.Elite and Mrs. Bright are equally effective teachers.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, we test if they are equally effective teachers, that is, the subtraction of their means is 0, hence:

$H_0: \mu_1 - \mu_2 = 0$

At the alternative hypothesis, we test if they are not equally effective teachers, that is, the subtraction of their means is not 0, hence:

$H_1: \mu_1 - \mu_2 \neq 0$

<h3>What is the distribution of the differences?</h3>

For Mrs. Elite, we have that:

$\mu_1 = 78, \sigma_1 = 10, n_1 = 30, s_1 = \frac{10}{\sqrt{30}} = 1.82574$

For Mrs. Bright, we have that:

$\mu_2 = 85, \sigma_2 = 15, n_2 = 25, s_2 = \frac{15}{\sqrt{25}} = 3$

For the distribution of differences, we have that:

$\overline{x} = \mu_1 - \mu_2 = 78 - 85 = -7$

$s = \sqrt{s_1^2 + s_2^2} = \sqrt{1.82574^2 + 3^2} = 3.5119$

<h3>What is the test statistic?</h3>

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{s}$

In which $\mu = 0$ is the value tested at the null hypothesis.

Hence:

$t = \frac{\overline{x} - \mu}{s}$

$t = \frac{-7 - 0}{3.5119}$

$t = -1.99$

Considering a<em> two-tailed test</em>, as we are testing if the mean is different of a value, with 30 + 25 - 2 = <em>53 df and a significance level of 0.1</em>, the critical value is of $|t^{\ast}| = 1.6741$ .

Since the absolute value of the test statistic is greater than the critical value, we reject the claim that Mrs.Elite and Mrs. Bright are equally effective teachers.

To learn more about the t-distribution, you can take a look at brainly.com/question/13873630

3 0

3 years ago