Answer:
C. 
General Formulas and Concepts:
<u>Calculus</u>
Differentiation
- Derivatives
- Derivative Notation
Derivative Rule [Product Rule]: ![\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bf%28x%29g%28x%29%5D%3Df%27%28x%29g%28x%29%20%2B%20g%27%28x%29f%28x%29)
Trig Derivatives
Logarithmic Derivatives
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>

<u>Step 2: Differentiate</u>
- Derivative Rule [Product Rule]:
![\displaystyle f'(x) = \frac{d}{dx}[ln(x)]cos(x) + ln(x)\frac{d}{dx}[cos(x)]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%27%28x%29%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bln%28x%29%5Dcos%28x%29%20%2B%20ln%28x%29%5Cfrac%7Bd%7D%7Bdx%7D%5Bcos%28x%29%5D)
- Logarithmic Derivative:
![\displaystyle f'(x) = \frac{1}{x}cos(x) + ln(x)\frac{d}{dx}[cos(x)]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%27%28x%29%20%3D%20%5Cfrac%7B1%7D%7Bx%7Dcos%28x%29%20%2B%20ln%28x%29%5Cfrac%7Bd%7D%7Bdx%7D%5Bcos%28x%29%5D)
- Trig Derivative:
![\displaystyle f'(x) = \frac{1}{x}cos(x) + ln(x)[-sin(x)]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%27%28x%29%20%3D%20%5Cfrac%7B1%7D%7Bx%7Dcos%28x%29%20%2B%20ln%28x%29%5B-sin%28x%29%5D)
- Simplify:

Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Differentiation
Book: College Calculus 10e
I believe the answer is 19.1 and then you round it from there. Because 173 is not an even number. Check with someone else though. Hope this helps!
(7x+2)(20-3x/4) = 140x + 40 - 21x²/4 - 3x/2 = -21/4 x² + 138 1/2 x + 40
this is one of those multiplications that doesn't make the result look any simpler...
Answer:
FD ≈ 252.8 feet
Step-by-step explanation:
By applying tangent rule in the given right triangle,
tan(20°) =
tan(20°) =
0.36397 =
FD =
FD = 252.77
FD ≈ 252.8 feet
Final Answer: 
Steps/Reasons/Explanation:
Question: Which expression is equivalent to 
<u>Step 1</u>: Expand by distributing terms.
×
× 
<u>Step 2</u>: Simplify
×
to
.
× 
<u>Step 3</u>: Simplify
×
to
.

<u>Step 4</u>: Remove parentheses and add.

~I hope I helped you :)~