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alexira [117]
4 years ago
13

ALGEBRA! NEED HELP!

Mathematics
2 answers:
Nimfa-mama [501]4 years ago
7 0
Since each edge's length is x, each face's are would be { x }^{ 2 }
And cubes have 6 faces. multiply 6 by { x }^{ 2 }, the formula is :6{ x }^{ 2 }
Amiraneli [1.4K]4 years ago
6 0
Surface area of a cube
cube=6 squares
square=2 equal sides
area of square=side^2
surface area of cube=6(area of square)=6side^2
side=x
SA=6x^2
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OverLord2011 [107]

Answer:

m=79

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Step-by-step explanation:

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7 0
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Absulute maximum definition
bonufazy [111]

Answer:

diffusion

Step-by-step explanation:

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6 0
3 years ago
Please help..<br> ASAP<br> Help<br> Please do all
Semenov [28]

Answer:

1) 257

2) 24^1=24

3) 47/8(Decimal: 5.875) How to: 5/1+7/8 = 40/80+7/8 = 40 + 7 / 8 <em>=</em><em> </em><em>4</em><em>7</em><em>/</em><em>8</em>

4)=920

5) =32.484

6) =33.444

7) = 4 : 1 How to: The GCF of 12 and 3 is 3 Divide both terms by the GCF, 3:

12 ÷ 3 = 4

3 ÷ 3 = 1 The ratio 12 : 3 can be reduced to lowest terms by dividing both terms by the GCF = 3 :

12 : 3 = 4 : 1

8) = 9 cups. How to: 2*3=6. so you multiply the other side (3) by 3 so 3*3=9 cups.

9) The second pack weighs more. How to: Since 45 ounces is 2.812 pounds (Formula

divide the mass value by 16) and 2.812 is less than 3 so second pack weighs more.

10) =26.6

Hope this helps!! If so please mark brainliest and rate/heart to help my account if it did!!

7 0
3 years ago
La distancia entre la tierra y el sol es de 1,5 . 10˄8 km, la distancia entre la Tierra y Júpiter es de 9,3 . 10˄8 km y Neptuno
Sonbull [250]

A) La distancia del Sol a Neptuno en notación científica es 45 x 10^8 km.  

B) Júpiter se encuentra a 930.000.000 kilómetros del Sol.  

C) La distancia del Sol a Neptuno es 30 veces mayor que la que hay a la Tierra.

Dado que la distancia entre la tierra y el sol es de 1,5 . 10˄8 km, la distancia entre la Tierra y Júpiter es de 9,3 . 10˄8 km y Neptuno está situado a 4.500.000.000 Km del Sol, para determinar:

A) Expresa en notación científica la distancia del sol a Neptuno  

B) Calcula la distancia a la que está situado Júpiter respecto al Sol  

C) Calcula cuantas veces es mayor la distancia del Sol a Neptuno que la que hay a la Tierra.

Deben realizarse los siguientes cálculos:

  • A) 4.500.000.000 = 45 x 100.000.000
  • 100.000.000 = 10^8
  • 4.500.000 = 45 x 10^8

  • B) 9.3 x 10^8 = X
  • 100.000.000 = 10^8
  • 9.3 x 100.000.000 = X
  • 930.000.000 = X

  • C) Tierra = 150.000.000
  • Neptuno = 4.500.000.000
  • 150 = 1
  • 4.500 = X
  • 4500 / 150 = X
  • 30 = X

Aprende más en brainly.com/question/1705769

8 0
3 years ago
4(x-2)(x-3)+7(x-2)(x-5)-6(x-3)(x-5)
katrin [286]
Do this need to be simplified or factored?
8 0
3 years ago
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