D midpoint of EC -----------------> FD parallel to AC and FD=AC/2=14/2=7
<span>2-EB=EA E midpoint of AB </span>
<span>DB=DC D midpoint BC ...............> ED=AC/2=2 </span>
<span>3-T midpoint of SR </span>
<span>U midpoint of QR ---------> TU = QS/2 </span>
<span>QS=2 TU = 4.4 </span>
<span>4- The same steps SR=2 UV=9 </span>
<span>5-N midpoint of KM </span>
<span>O midpoint of ML </span>
<span>* NO parallel to Kl</span>
Answer:
1- 5xy³√5y
2- 2xy²∛3y²
Step-by-step explanation:
√125x²y^7=
√25*5x²y^6y
5xy³√5y
2) ∛24x³y^8=
∛2³*3x³y^8=
2xy²∛3y²
A) x * y = 42 (or x = 42/y)
B) x + y = 23
B) 42/y + y = 23
42 + y^2 = 23y
y^2 -23y + 42 = 0
The numbers are 21 and 2
For
, we have
and so
which is, again, only valid for
.
The answer to this question is x=4.
