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2 years ago

15

For what value of p the equation [p-3]x²+4[p-3]+4=0

1 answer:

Vikentia [17]2 years ago

3 0

Step-by-step explanation:

(p-3)[x²+4]+4=0

(p-3)[x²+4]=-4

(p-3)=-4/x²+4

p=-4/x²+4+3

p=-4+3(x²+4)/x²+4

p= -4+3x²+12/x²+4

p=8+3x²/x²+4

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