Answer:c- sixty nine hundredths
Step-by-step explanation:
three tenths can be expressed in decimal as 3/10
thirty nine hundredths can be expressed in decimal as 39/100
Therefore the sum of three tenths plus thirty nine hundredths equals
3/10 +39/100
We first find the l.c.m of the two fractions equals 100 so we have 100 as the denominator
then 100 divided by 10 multiplied by 3 +100 divided by 100 multiplied by 39 as illustrated below gives the answer
3/10 +39/100
=30+39/100
=69/100= sixty nine hundredths
C) no solution
use desmos.com to help with these problems
Answer:
⟨-5, -1⟩
Step-by-step explanation:
Vector:
A vector is given by its endpoint subtracted by its initial point.
Vector u has initial point at (3, 9) and terminal point at (–7, 5)
Then
Vector v has initial point at (1, –4) and terminal point at (6, –1).
Then
What is u + v in component form?
⟨-5, -1⟩ is the answer.
The point (2, -5) would not be one of the correct vertices of the reflected shape.
When we reflected a shape across the line y=x, we just replace the x's with y's and y's with x's.
Our new points are (5, 2) (4, 6) and (3, 3). None of the points contain negative numbers.
Answer:
Your final answer is either
x≥-2 if your initial inequality was
6x+2≤2(5-x)
OR
x≤-2
if your initial inequality was
6x+2≥2(x-2)
Step-by-step explanation:
As shown you have an equality, not an inequality.
-6x+2=2(5-x) distribute through parenthesis
-6x+2=2(5)+2(-x)
-6x+2=10-2x add 2x to both sides
2x-6x+2=10-2x+2x
-4x+2=10 subtract 2 from both sides
-4x+2-2=10-2
-4x=8 divide both sides by -4
-4x/(-4) = 8/(-4)
x = -2
With the ≥ or ≤ sign you would solve the exact same way
except for the point where when dividing both sides by
-4 requires you to reverse the inequality.
Your final answer is either
x≥-2 if your initial inequality was
6x+2≤2(5-x)
OR
x≤-2
if your initial inequality was
6x+2≥2(x-2)
