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4 years ago

What is the solution of the quadratic equation?

Mathematics

2 answers:

NISA [10]4 years ago

5 0

The answer is A. After you square root both sides, you have to add 3 to both sides and then divide both sides by 4.

Maksim231197 [3]4 years ago

3 0

I agree the answer to this question is A

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Find the area of a triangle with base of 15 m and altitude of 12 m.

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Triangle Area = 90

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The standard equation of a circle with center (h.k) and radius r is (% - hy * (y - Ky = p. Which

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3 years ago

3/5n+15=10+2/5n what is n

Nutka1998 [239]

$\textsf{Hey there!}$

$\mathsf{\dfrac{3}{5}n +15=10+\dfrac{2}{5}n}$

$\mathsf{\bf{SUBTRACT}\ \mathsf{by\ \dfrac{2}{5}n\ from\ both\ of\ your\ sides}}$

$\mathsf{Like: \dfrac{3}{5}n+15-\dfrac{2}{5}n=\dfrac{2}{5}n+10-\dfrac{2}{5}n}$

$\mathsf{\bf{CANCEL: \dfrac{3}{5}+\dfrac{2}{5}}}\textsf{out\ because that gives you\ 1}$

$\textsf{Solve\ the set we have left over}$

$\mathsf{Our\ new\ equation\ becomes: \dfrac{1}{5}n+15=10}$

$\mathsf{\bf{SUBTRACT}}\textsf{ by 15 on both of your sides}$

$\mathsf{\dfrac{1}{5}n+15-15=10-15}$

$\mathsf{Cancel\ out: 15-15\ because\ that\gives\ you\ 0 }$

$\mathsf{Keep: 10-15\ because\ it\ helps\ us\ solve\ for\ your\ n }$

$\mathsf{10-15=-5}$

$\mathsf{New\ equation: \dfrac{1}{5}n=-5}$

$\mathsf{\bf{MULTIPLY}\mathsf{\ both\ sides\ by\ 5}}$

$\mathsf{\dfrac{1}{5}n\times5=5\times-5}$

$\mathsf{Cancel\ out\ \dfrac{1}{5}\times5 \ because \ it \ gives \ us \ 1}$ $\mathsf{Keep: 5\times -5\ because\ it\gives\ us\ the\ value\ of\ your\ n}$