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Fynjy0 [20]
3 years ago
13

A lemming running 3.22 m/s runs off a horizontal cliff. It lands in the water 7.54 m from the base of the cliff. How much time w

as it in the air? (Unit = s)
Physics
1 answer:
LekaFEV [45]3 years ago
7 0

Answer: 2.34s

Explanation:

Given the following :

Horizontal Velocity(V) = 3.22m/s

Horizontal Distance = 7.54m

Therefore, the time spent in the air can be calculated thus:

Using the relation:

Speed = distance / time

3.22m/s = 7.54m / time

Time = 7.54m / 3.22m/s

Time = 2.34s

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Answer:

They will meet at a distance of 7.57 m

Given:

Initial velocity of policeman in the x- direction, u_{x} = 10 m/s

The distance between the buildings, d_{x} = 2.0 m

The building is lower by a height, h = 2.5 m

Solution:

Now,

When the policeman jumps from a height of 2.5 m, then his initial velocity, u was 0.

Thus

From the second eqn of motion, we can write:

h = ut + \frac{1}{2}gt^{2}

h = \frac{1}{2}gt^{2}

2.5 = \frac{1}{2}\times 10\times t^{2}

t = 0.707 s

Now,

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d_{x} = u_{x}t + \frac{1}{2}gt^{2}

d_{x} = 10\times 0.707 + \frac{1}{2}\times 10\times 0.5 = 9.57 m

The distance they will meet at:

9.57 - 2.0 = 7.57 m

   

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Answer:

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