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2 years ago

1. How does speed affect the amount of kinetic energy in a moving object? Explain how you

Physics

1 answer:

TiliK225 [7]2 years ago

5 0

Explanation:

The kinetic energy of a moving object is directly proportional to its mass and directly proportional to the square of its velocity. This means that an object with twice the mass and equal speed will have twice the kinetic energy while an object with equal mass and twice the speed will have quadruple the kinetic energy.

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How would you describe the behavior of particles in a solid?

Minchanka [31]

How would you describe the behavior of particles in a solid?

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2 years ago

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A force of 210 N is applied to an object and the object accelerates at 14m/s2. Determine the mass of the object in kg.

lisabon 2012 [21]

Answer:

15 kg

Explanation:

F = m*a

F/a = m

210/14 = 15 kg

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2 years ago

Please Help! The thing is in the photo.

ivolga24 [154]

The reaction 4Al + 3O₂ → 2Al₂O₃ is a synthesis or also called combination reaction because reactants combine to produce a new compound (Option 2).

<h3>What is a synthesis combination reaction?</h3>

In chemistry, a synthesis or combination reaction is any type of chemical reaction in which two or more molecules called reactants combine to produce one or more molecules called products of such reaction.

Therefore, with this data, we can see that a synthesis or combination reaction is a chemical process where two or more molecules combine to produce a new molecule known as a product.

Learn more about synthesis combination reactions here:

brainly.com/question/14703806

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1 year ago

Beth moves a 15 N book 20 meters in 10 seconds. How much power was produced?

Mice21 [21]

Answer:

30 Watts

Explanation:

Power = Work/Time

Work = Force*Distance

Power = Force * Distance / Time

Power = 15 N * 20 meters / 10 sec

Power = 30 Watts

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3 years ago

A 0.54 kg air hockey puck is initially at rest. What will it's kinetic energy energy be after a net force of 0.56 N acts on it f

Rufina [12.5K]

Answer:

Kf = 470 mJ

Explanation:

According the work-energy theorem, the change in the kinetic energy of one object, is equal to the net work done on it.
Since the puck is initially at rest, the change is kinetic energy is just the final kinetic energy of the puck.
Assuming that the net force is horizontal, and causes a horizontal displacement also, we can find the net work on the puck as follows:

$W_{net} = F_{net} * \Delta X = 0.56 N * 0.84 m = 0.47 J = 470 mJ (1)$

As we have already said, (1) is equal to the final kinetic energy of the puck:
⇒ Kf = 470 mJ (2)

8 0

2 years ago