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rosijanka [135]
3 years ago
5

Which of the following is equivalent to log40 (8) rounded to three decimal places?

Mathematics
1 answer:
lilavasa [31]3 years ago
4 0
\log_{40}8=\dfrac{\ln8}{\ln40}\approx0.564

Answer C.
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Can somebody help me
saveliy_v [14]

Answer:

Y=5

You must first divide b (-10) by two and square it to know what you need to make a perfect square (25). You must then add or subtract the amount to make C (-13) into that number (add 38). Don't forget to do it on the other side too! (3 becomes 41) You then factor the left side. ((Y-5)^2=41) The result is your answer. (Y=5)

6 0
3 years ago
Ratio tables 10 every 15 minutes how many in a hour
BaLLatris [955]

Answer:

40

Step-by-step explanation: If 10 : 15, then 4 times both of those should be an hour. This would be 40 : 60. That is why 40 is the correct answer.

6 0
3 years ago
Read 2 more answers
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m_a_m_a [10]

Second option, just do Pemdas backwards.

5 0
3 years ago
The Smith family wants to fence their yard. The yard is 96 meters and 52 meters wide. How much fencing will they need?
Nadya [2.5K]

Answer:

4,992 meters of fence

Step-by-step explanation:

7 0
2 years ago
It is given that one number is 6 more than another. If three times the sum of the two numbers is equal to 22 more than the large
Irina-Kira [14]

Answer:

First number=22

Second number=28

Step-by-step explanation:

Since you don't know either of the numbers we can call the first number x. The second number is the first number plus 6 or x+6. The sum is 22 more than the larger number so x+6+22 or x+28. Using this we can create the equation x+x+6=x+28. In order to isolate x we would subract x from both sides ending up with x+6=28. Then subract 6 from both sides to get x=22. This means the first number equals 22. Then to solve for the second number you plug 22 in for x to get the equation 22+6= the second number, so the second number is equal to 28. Look below for just the equation.

x+x+6=x+6+22

2x+6=x+28

-x -x

x+6=28

-6. -6

x=22

22+6

=28

22+28= 28+22

50=50

6 0
3 years ago
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