1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Effectus [21]
3 years ago
12

Help me plz!!!!!!! test tomorrow

Mathematics
1 answer:
Alex3 years ago
7 0

Answer:

The number of movies purchased is 5

Step-by-step explanation:

40.00 + 3.50 = 43.50

43.50 + 3.50 = 47.00

47.00 + 3.50 = 50.50

50.50 + 3.50 = 54.00

54.00 + 3.50 = 57.50

so if you add 3.50 to 40, 5 times you'll get 57.50

Hope it helped

You might be interested in
Please could you find the answers to the questions in the attachment.
Fudgin [204]
(\frac{x1+x2}{2} , \frac{y1+y2}{2})we need 3 equations
1. midpoint equation which is  (\frac{x1+x2}{2} , \frac{y1+y2}{2}) when you have 2 points

2. distance formula which is D= \sqrt{(x2-x1)^{2}+(y2-y1)^{2}}

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height


so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=(\frac{11+19}{2} , \frac{10+6}{2})
midpoint=(\frac{30}{2} , \frac{16}{2})
midpoint= (15,8)

point x=(15,8)



y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=(\frac{5+21}{2} , \frac{8+0}{2})
midpoint=(\frac{26}{2} , \frac{8}{2})
midpoint=(13,4)

Y=(13,4)



legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= \sqrt{(19-11)^{2}+(6-10)^{2}}
D= \sqrt{(8)^{2}+(-4)^{2}}
D= \sqrt{64+16}
D= \sqrt{80}
D= 4 \sqrt{5}
BC=4 \sqrt{5}





X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= \sqrt{(13-15)^{2}+(4-8)^{2}}
D= \sqrt{(-2)^{2}+(-4)^{2}}
D= \sqrt{4+16}
D= \sqrt{20}
D= 2 \sqrt{5}
XY=2 \sqrt{5}


the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC=4 \sqrt{5} and XY=2 \sqrt{5}

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= \sqrt{(21-5)^{2}+(0-8)^{2}}
D= \sqrt{(16)^{2}+(-8)^{2}}
D= \sqrt{256+64}
D= \sqrt{320}
D= 4 \sqrt{2}
AD=4 \sqrt{2}


so we have
AD=4 \sqrt{2}
BC=4 \sqrt{5} 
XY=2 \sqrt{5}

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
(4 \sqrt{2}+4 \sqrt{5}) times 1/2 times 2 \sqrt{5} =
(4 \sqrt{2}+4 \sqrt{5}) times \sqrt{5} [/tex] =
4 \sqrt{10}+4*5=4 \sqrt{10}+20=80 \sqrt{10}=252.982


























X=(15,8)
Y=(13,4)
BC=4 \sqrt{5}
XY=2 \sqrt{5}
Area=80 \sqrt{10} square unit or 252.982 square units







7 0
3 years ago
There are 16 girls and 20 boys in the school band. Express an equivalent ratio of boys to total number of students in the school
Alex17521 [72]

Answer:

4:5

Step-by-step explanation:

half of 16 is 8, and half of 8 is 4

and half of 20 is 10, and half of 10 is 5

hope i helped man

8 0
3 years ago
A recreation center is offering special prices on its pool passes and gym memberships for the summer. On the first day of the of
s344n2d4d5 [400]

Answer:

In grade 8, students learned that some systems of linear equations have many solutions. This warm-up reminds students about this fact, while also prompting them to use what they learned in this unit to better understand what it means for a system to have infinitely many solutions.

The first equation shows two variables adding up to 3, so students choose a pair of values whose sum is 3. They notice that all pairs chosen are solutions to the system. Next, they try to find a strategy that can show that there are countless other pairs that also satisfy the constraints in the system. Monitor for these likely strategies:

Solving by graphing: The graphs of the two equations are the same line, so all the points on the line are solutions to the system.

Solving by substitution: The first equation can be rearranged to . Substituting for in the second equation gives or or . This equation is true no matter what is.

Solving by elimination: If we multiply the first equation by 4, rearrange the second equation to , and then subtract the second equation from the first, the result is . Subtracting from each side gives , which is true regardless of what or is.

Reasoning about equivalent equations: If we rearrange the second equation so that the variables are on the same side , we can see that this equation is a multiple of the first and are equivalent. This means they have the exact same solution set, which contains infinite possible pairs of and .

Identify students using different strategies and ask them to share their thinking with the class later.

Making graphing technology available gives students an opportunity to choose appropriate tools strategically (MP5).

Step-by-step explanation:

✒✒✏✂✂✏✒✏✒✂✏✂✏✒✂✒✂✂✂✏✂✒✂✂✂✒✏✏✏✒✒✏✏

7 0
3 years ago
(3 x 10-7) x (8 x 10 )
charle [14.2K]

Answer:

1840

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Find the mean median and mode (I NEED HELP ASAP)
Lina20 [59]

Answer:

12) mode= no mode

     mean=62

     median=81

13) mode=74

mean=78

median =74

14) mode=80

mean=73

median=70

15)mode=70

mean=74

median=75

16)mode-no mode

mean=51

median=45

17)mode=86

mean=55

median=77

18)mode=no mode

mean=79

median=78

19)mode=70

mean=77

median=79

hope that helps :D

8 0
3 years ago
Read 2 more answers
Other questions:
  • Which expression is equal to 5/(sqrt)11?
    9·2 answers
  • Round 614,594 to the nearest ten thousand.
    14·1 answer
  • I need help please?!!!):
    6·1 answer
  • The equation of the line of best fit is F=1.5h -4.3, where F is foot length in millimeters and h is height in centimeters. Expla
    7·1 answer
  • I need help to start this problem. Can some help? The problem is 5k+6-k≥-14
    8·2 answers
  • Can anyone answer this question for me ?
    8·2 answers
  • Determine the missing frequency​
    5·1 answer
  • You and your friend are standing back-to-back. Your friend runs 14 feet forward and then 7 feet right. At the same time, you run
    15·1 answer
  • 3 + 6x = 15?<br> pls help :D
    6·1 answer
  • Hi I need help asap <br><br> I don’t understand it can u help me for a and b
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!