Complete Question
Kelvin finished 2/3 of his test in a 1/2 hour. Express this rate in hours per test.
Answer:
3/4 hours per test
Step-by-step explanation:
2/3 of his test = 1/2 hour
This rate in hours per test is calculated as:
x = 1/2 /2/3
x = 1/2 hour ÷ 2/3 test
x = 1/2 × 3/2
x = 3/4 hours per test
This rate in hours per test is given as 3/4 hours per test
Answer:
Use ≈ (approximately equal) sign as the scientific notation.
Step-by-step explanation:
(a) 0.001872 ≈ 0.0019
(b) 0.3411 ≈ 0.34
(c) 0.000845 ≈ 0.00085
*Zeros before non-zero numbers are not significant.
*Zeros appearing between two non-zero digits are significant.
Hope this helps!!
Answer: 15e^5x
Step - by - step
y=3e^5x - 2
By the sum rule, the derivative of 3e^5x - 2 with respect to x is d/dx [ 3e^5x ] + d/dx [-2].
d/dx [ 3e^5x ] + d/dx [ -2 ]
Evalute d/dx [ 3e^5x ]
Since 3 is constant with respect to x , the derivative of 3e^5x with respect to x is
3 d/dx [ e^5x ].
3 d/dx [ e^5x ] + d/dx [ -2 ]
Differentiate using the chain rule, which states that d/dx [ f(g(x))] is f' (g(x)) g' (x) where f(x) = e^x and g(x) = 5x.
To apply the Chain Rule, set u as 5x.
3 ( d/du [ e^u] d/dx [5x] ) + d/dx [ -2]
Differentiate using the Exponential rule which states that d/du [ a^u ] is a^u ln(a) where a=e.
3( e^u d/dx[5x] ) + d/dx [ -2 ]
Replace
3(e^5x d/dx [5x] ) + d/dx [ -2 ]
3(e^5x( 5 d/dx [x] )) + d/dx [ -2 ]
Diffentiate using the Power Rule which states that d/dx [x^n] is nx^n-1 where n=1.
3(e^5x(5*1)) + d/dx [-2]
3 ( e^5x * 5 ) + d/dx [-2]
Multiply 5 by 3
15e^5x + d/dx [-2]
Since -2 is constant with respect to x, the derivative of -2 with respect to x is 0.
15e^5x + 0
15e^5x
Answer:
$51.41
Step-by-step explanation:
trust
Answer:
1
Step-by-step explanation:
One member in the graph only went one time which is fewer than two times.
