answer is C. 252 ft^2
split the figure into two pieces and first figure out the rectangle (shown in turquoise).
If you multiply the width and length (18*6) you should get 108.
Then figure out the trapezoid (in magenta). the formula is (a+b)/2*h where a and b are the bases and h is the height. the bases are given, 6 and 18. to find the height, subtract the entire figure's height by 6, which is 18-6 and gives us 12. so the formula converted to this problem is (6+18)/2*12. simplify parenthesis and get 24/2*12. 24/2=12, so multiply 12*12. The area of the trapezoid is 144. Add the areas of both figures together and get 252.
Answer:
Step-by-step explanation:
The max and min values exist where the derivative of the function is equal to 0. So we find the derivative:
Setting this equal to 0 and solving for x gives you the 2 values
x = .352 and -3.464
Now we need to find where the function is increasing and decreasing. I teach ,my students to make a table. The interval "starts" at negative infinity and goes up to positive infinity. So the intervals are
-∞ < x < -3.464 -3.464 < x < .352 .352 < x < ∞
Now choose any value within the interval and evaluate the derivative at that value. I chose -5 for the first test number, 0 for the second, and 1 for the third. Evaluating the derivative at -5 gives you a positive number, so the function is increasing from negative infinity to -3.464. Evaluating the derivative at 0 gives you a negative number, so the function is decreasing from -3.464 to .352. Evaluating the derivative at 1 gives you a positive number, so the function is increasing from .352 to positive infinity. That means that there is a min at the x value of .352. I guess we could round that to the tenths place and use .4 as our x value. Plug .4 into the function to get the y value at the min point.
f(.4) = -48.0
So the relative min of the function is located at (.4, -48.0)
Answer: A number times 5 plus 2
Step-by-step explanation:
Answer:
a) √2
b) √(5a)
c) √3
d) -√2
e) -√(3x)
Step-by-step explanation:
This problem set makes use of the relation ...
... a√b = √(a²b)
a) (1/3)√18 = √(18·(1/3)²) = √(18/9) = √2
b) 5√(a/5) = √(25a/5) = √(5a)
c) 2√(3/4) = √(4·3/4) = √3
d) -10√0.02 = -√(100·0.02) = -√2
e) -(1/2)√(12x) = -√(12x/4) = -√(3x)
What do you want me to answer I’ll help you
