The answer is:
4x+2y=11} 4x+2y=11} x=2-2y
x-2=-2y } x+2y=2 } x=2-2(-3/6)
x=2-(-6/6)
4(2-2y)+2y=11 x=2-(-1)
8-8y+2y=11 x=3
8-6y=11
-6y=11-8
-6y=3/-6
y=-3/6=-1/2
So for my opinion the solution is A.(3,-1/2)
Answer:
add (12/2)^2 to both sides
Step-by-step explanation:
x^2-12x=16
x^2 -12x + (12/2)^2 = 16 + (12/2)^
x- (12/2)^2=52
(x-6)^2=52
Answers:
x= -2 root 3 +6
x= 2 root 3 +6
For a function, domain means the x value & range is the y value. So, simply, substitute each value in the domain for the x in your function, and you'll find the range.
Here're the answers:
g(0)=(0)^2+2
g(0)=2
g(2)=(2)^2+2
g(2)=6
g(5)=(5)^2+2
g(5)=27
g(9)=(9)^2+2
g(9)=83
Hope this helps!
Isolate the x. Note the equal sign. What you do to one side, you do to the other.
First, add 9 to both sides
3/4x - 9 (+9) = 27 (+9)
3/4x = 36
Next, multiply 4/3 to both sides
(4/3)(3/4)x = 36(4/3)
x = 36(4/3)
Simplify.
x = 12(4)
x = 48
48 is your answer for x.
hope this helps
The answer is -1 because it's smaller than 1
