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valentina_108 [34]
3 years ago
11

Que expresión trigonometrica se podria usar para calcular la longitud del cateto XZ​

Mathematics
1 answer:
lana [24]3 years ago
7 0
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Solve 4x^4 - 37x^2 + 9 = 0 for ALL its solutions
SVETLANKA909090 [29]
Solve for x over the real numbers:4 x^4 - 37 x^2 + 9 = 0
Substitute y = x^2:4 y^2 - 37 y + 9 = 0
The left hand side factors into a product with two terms:(y - 9) (4 y - 1) = 0
Split into two equations:y - 9 = 0 or 4 y - 1 = 0
Add 9 to both sides:y = 9 or 4 y - 1 = 0
Substitute back for y = x^2:x^2 = 9 or 4 y - 1 = 0
Take the square root of both sides:x = 3 or x = -3 or 4 y - 1 = 0
Add 1 to both sides:x = 3 or x = -3 or 4 y = 1
Divide both sides by 4:x = 3 or x = -3 or y = 1/4
Substitute back for y = x^2:x = 3 or x = -3 or x^2 = 1/4
Take the square root of both sides:Answer(s):  x = 3 or x = -3 or x = 1/2 or x = -1/2
4 0
4 years ago
How do i do number 2 and answer for all of them
meriva
For numbers 2-6, use inverse operations. Instead of subtracting add and if you are adding, subtract in the problem. For number 7, subtract $5 to $13. Hope this helps.
4 0
3 years ago
One number is four times another number. If their sum is 95, what are the numbers?
nikdorinn [45]
Let x be one number and y be the other.

#1 - Set up a system of equations.
4x = y
x + y = 45

#2 - Solve the system by substitution.
x + (4x) = 45
5x = 45
x = 9

(9) + y = 45
y = 36
8 0
4 years ago
Read 2 more answers
Verify the identity. cos (x - y) - cos (x + y) = 2 sin x sin y
nignag [31]
Let's start from the left side, and manipulate it to get the right side, which would prove the identity.

We know that:

i) \displaystyle{ \cos(x-y)=\cos x \cos y+\sin x \sin y

ii) \displaystyle{ \cos(x+y)=\cos x \cos y-\sin x \sin y.

From the above fundamental identities, we can rewrite the left hand side as:

\displaystyle{ \cos x \cos y+\sin x \sin y-(\cos x \cos y-\sin x \sin y)=


\displaystyle{ \cos x \cos y+\sin x \sin y-\cos x \cos y+\sin x \sin y=2\sin x \sin y,

which is what we needed to show.
5 0
3 years ago
Question: I see 8 more lilacs than roses. I see 9 roses. How many lilacs do I see? Thanks
harkovskaia [24]
If you see 8 more roses than lilacs, and there are 9 lilacs, then the answer would be 17 lilacs because 8 + 9 = 17. If you were to answer it through algebra, it would be 8 + 9 = x <span />
5 0
3 years ago
Read 2 more answers
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