Question

(3) 1. HCl NaOH: In Part I: An aqueous solution of sodium hydroxide reacts with an aqueous solution of hydrochloric acid, yielding water. Write the balanced molecular, ionic, and net ionic equations

Answer 1

Answer:

Explanation:

molecular equation: HCl(aq)+NaOH(aq)➡NaCl(aq)+H2O(l)

The two reactants i.e. sodium hydroxide and hydrochloric acid will dissociate completely in aqueous solution to form respective cations and anions

NaOH(aq)➡Na+(aq) + OH-(aq)

HCl(aq)➡H+(aq) + Cl-(aq)

Now when these two reactants are mixed, the hydroxide ions and the hydrogen ions will neutralize each other to form water while the sodium cation and chloride anions will act as a spectator ions.

Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq)➡Na+(aq) + Cl-(aq) +H2O(l)

Now strike out the spectators ions from both side of the arrow in the above equation and you"ll get the net ionic equation as:

H+(aq) + OH-(aq)➡H2O(l)

Answer 2

Answer:HCl(aq) + NaOH (aq) -> NaCl (aq) + H2O(l)

Explanation:

The reaction of HCl and NaOH is a neutralization reaction. When an acid and a base react salt and water is produced.

HCl(aq) + NaOH (aq) ----> NaCl (aq) + H2O(l)

Because the reactants and products are ionic compounds, they exist as ions in a solution.

H+(aq) + Cl-(aq) + Na+(aq) + OH-(aq) -------> Na+(aq) + Cl-(aq) + H2O(l)

The aim of a neutralization reaction is the formation of water. Na+(aq) + Cl-(aq) remain the same on both the reactants side and the products side, the net ionic reaction will be

H+(aq) + OH-(aq) -------> H2O(l)