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Vikentia [17]
3 years ago
13

Explain how science can help you make more informed decisions about buying products that make incredible claims.

Chemistry
1 answer:
LenaWriter [7]3 years ago
7 0
You will know;
1. know what products are 
2. know how they work
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FEDE
borishaifa [10]

Answer:

omeone tell me something

Shut up and take my money

I've got pockets full of gold

No, I don't owe nothing

Stop acting funny

I've seen greedy people hungry

Up in swarms, I've seen them running

Coming for more

Explanation:

6 0
4 years ago
How many moles of n are in 0.225 g of n2o?
katrin2010 [14]
<span>First, divide the mass of N2O by it's molar mass of 46 g/mol to determine the number of moles of N2O, then multiply that number by two since there are two moles of N in each mole of the compound N2O. This results in a final answer of 9.78X10^-3 moles of N in 0.225g of N2O.</span>
5 0
3 years ago
A solid piece of lead has a mass of 23.94g and a volume of 2.10cm^3. from these data, calculate the density of lead in si units
jeyben [28]
A density of a substance is constant. It is an extensive property, meaning it does not depend on the amount of substance because it is a ratio of mass to volume. No matter how much of each there is, they would always have a fixed ratio called density. For lead, the density is

Density = mass/volume
Density = 23.94 g/ 2.10 cm³
Density = 11.4 g/cm³
4 0
3 years ago
Using noble gas notation write the electron configuration for the chromium(II) ion
zzz [600]
Since chromium has 24 as its atomic number (which mean that it has 24 proton and 24 electron in neutral ground state), the electron configuration for the chromium would be :

1s^2 , 2s^2 , 2p^6 , 3s^2, 3p^6 , 3d^5 , 4s^1
6 0
3 years ago
Liquid sodium is being considered as an engine coolant. How many grams of liquid sodium (minimum) are needed to absorb 8.60 MJ o
Alecsey [184]

Answer: 64.216\times 10^4grams of liquid sodium is required.

Explanation: To calculate the mass of liquid sodium, we use the formula:

q=nc\Delta T\\q=\frac{m}{M}c\Delta T

where,

q = heat required, 8.60MJ=8.60\times 10^6J   (Conversion factor: 1MJ = 1000000J)

m = Mass of liquid sodium, ?g

M = Molar mass of liquid sodium, 23g/mol

c = Specific heat capacity, 30.8J/Kmol

\Delta T = change in temperature,  \Delta T=(510-500)K=10K    (Conversion factor: 0°C = 273K)

Putting values in above equation, we get:

8.60\times 10^6J=\frac{m}{23g/mol}\times 30.8J/Kmol\times 10K

m=64.216\times 10^4grams

5 0
3 years ago
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