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3 years ago

10 + 7x = -8 ( x -7)

Mathematics

1 answer:

tresset_1 [31]3 years ago

4 0

10+7x = -8x+56

15x=46

x=46/15

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What is the factorization of 729^15+1000?

igomit [66]

Answer:

The factorization of $729x^{15} +1000$ is $(9x^{5} +10)(81x^{10} -90x^{5} +100)$

Step-by-step explanation:

This is a case of factorization by sum and difference of cubes, this type of factorization applies only in binomials of the form $(a^{3} +b^{3} )$ or $(a^{3} -b^{3})$ . It is easy to recognize because the coefficients of the terms are perfect cube numbers (which means numbers that have exact cubic root, such as 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, etc.) and the exponents of the letters a and b are multiples of three (such as 3, 6, 9, 12, 15, 18, etc.).

Let's solve the factorization of $729x^{15} +1000$ by using the sum and difference of cubes factorization.

1.) We calculate the cubic root of each term in the equation $729x^{15} +1000$ , and the exponent of the letter x is divided by 3.

$\sqrt[3]{729x^{15}} =9x^{5}$

$1000=10^{3}$ then $\sqrt[3]{10^{3}} =10$

So, we got that

$729x^{15} +1000=(9x^{5})^{3} + (10)^{3}$ which has the form of $(a^{3} +b^{3} )$ which means is a sum of cubes.

Sum of cubes

$(a^{3} +b^{3} )=(a+b)(a^{2} -ab+b^{2})$

with $a= 9x^{5}$ y $b=10$

2.) Solving the sum of cubes.

$(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)((9x^{5})^{2}-(9x^{5})(10)+10^{2} )$

$(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)(81x^{10}-90x^{5}+100)$

8 0

3 years ago

Help plz I need big help someone plz help me with this question!

ozzi

Answer:

Step-by-step explanation to be honest probably 12 if not i’m so sorry

3 0

3 years ago

What is the Quotient of 1 and 2/3 divided by 2 and 3/5

Nostrana [21]

Answer:

25/39

Step-by-step explanation:

For division of mixed numbers, it often works well to first convert them to improper fractions. Then the division proceeds in the usual way: "invert and multiply", or "dot, swap."

$1\dfrac{2}{3}\div2\dfrac{3}{5}=\dfrac{5}{3}\div\dfrac{13}{5}=\dfrac{5}{3}\cdot\dfrac{5}{13}\\\\=\dfrac{5\cdot5}{3\cdot13}=\boxed{\dfrac{25}{39}}$