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balu736 [363]
4 years ago
15

Richard is driving home to visit his parents. 135{\rm mi} of the trip are on the interstate highway where the speed limit is 65{

\rm mph} . Normally Richard drives at the speed limit, but today he is running late and decides to take his chances by driving at 73{\rm mph} . How many minutes does he save?
Physics
1 answer:
nydimaria [60]4 years ago
6 0

Answer:

time spent = 0.2276

Explanation:

given data

distance = 135 mi

usual speed = 65 mph

today speed = 73 mph

solution

we get here time that is express as

time = \frac{distance}{speed}    ...................1

usual time = \frac{135}{65}  = 2.0769 h

today time = \frac{135}{73} = 1.8493 h

so we get here time spent as

time spent = 2.0769 h - 1.8493 h

time spent = 0.2276

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A mountain climber stands at the top of a 50.0 m cliff hanging over a calm pool of water. The climber throws two stones vertical
Sonbull [250]

Answer:

a. t=2.997\ s is the time after which the two stone hit the water surface.

b. u_2=1.998\ m.s^{-1}

c. v_1=31.3688\ m.s^{-1}   &  v_2=31.3686\ m.s^{-1}

Explanation:

Given:

  • height of the cliff, h=50\ m
  • time gap between the projection of stones, \Delta t=1\ s
  • initial velocity of first stone, u_1=+2\ m.s^{-1}

Here positive sign means that the stone is thrown vertically downward in the direction of gravity.

a.

Using equation of motion:

h=u_1.t+\frac{1}{2} g.t^2

50=2t+4.9t^2

t=2.997\ s is the time after which the two stone hit the water surface.

b.

using the equation of motion for second stone:

h=u_2.t+\frac{1}{2} g.t^2

50=u_2\times 2.997+4.9\times 2.997^2

u_2=1.998\ m.s^{-1}

c.

Final velocity of the stone at the instant of touching the water surface:

v_1^2=u_1^2+2.g.h

v_1^2=2^2+2\times 9.8\times50

v_1=31.3688\ m.s^{-1}

&

v_2^2=u_2^2+2g.h

v_2^2=1.998^2+2\times 9.8\times 50

v_2=31.3686\ m.s^{-1}

6 0
4 years ago
A box is being pushed across the floor at a constant velocity with an
Oksana_A [137]

Answer:

<em>Magnitude of frictional force = 30 N</em>

Explanation:

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

Fn=m.a

The net force is the vector addition of each individual force. If the sum of all the forces acting on an object is zero, then the acceleration is zero. That means the object moves at a constant speed or is at rest.

When an object is pushed across a horizontal rough surface, there are two forces acting in the direction of the motion: The applied force and the frictional force.

If the applied force is greater than the frictional force, then the object moves at a constant positive acceleration. If the frictional force is greater than the applied force, then the object won't move at all (if it was at rest) or will start a deaccelerated motion (braking).

Finally, if both forces are equal, the object will move at a constant speed or remains at rest. Since the box is moving at a constant speed, we can conclude the frictional force equals the applied force:

Magnitude of frictional force = 30 N

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4 years ago
What happens to a catalyst after a chemical reaction has occurred
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It goes away and goes off to catalyze more things. Imagine it like the priest of a wedding. S/He's just catalyzing the bond between two entities, and s/he will continue to do that, not having anything to do with the bond past its creation.
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An 85 kg object is moving at a constant speed of 15 m/s in a circular path,which has a radius of 20 meters. What centripetal for
vova2212 [387]
As always,. F = M A. Centripetal acceleration = V-squared / R. So F=M V-squared/R. =. 85 x 225 / 20. = 956.25 Newton's (about 215 pounds). That's the force required to keep that mass moving at that speed around that circle. If the force is less, or not there, then the 85 kg moves slower, or leaves that path.
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Difference between Heterozygous and homozygous ?
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The difference between heterozygous and homozygous is that heterozygous has to do with different genes, while homozygous has to do with the same genes.
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