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balu736 [363]
3 years ago
15

Richard is driving home to visit his parents. 135{\rm mi} of the trip are on the interstate highway where the speed limit is 65{

\rm mph} . Normally Richard drives at the speed limit, but today he is running late and decides to take his chances by driving at 73{\rm mph} . How many minutes does he save?
Physics
1 answer:
nydimaria [60]3 years ago
6 0

Answer:

time spent = 0.2276

Explanation:

given data

distance = 135 mi

usual speed = 65 mph

today speed = 73 mph

solution

we get here time that is express as

time = \frac{distance}{speed}    ...................1

usual time = \frac{135}{65}  = 2.0769 h

today time = \frac{135}{73} = 1.8493 h

so we get here time spent as

time spent = 2.0769 h - 1.8493 h

time spent = 0.2276

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How do your results from ray tracing compare to your results from using the thin-lens equation?
EastWind [94]

Answer:

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Substitute u = -20cm ( due to negative magnification)and v = 10cm into the lens formula to get the focal length f

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3 years ago
to move a resting box of 100 Newton on the ground with kinetic friction coeficient of 0,250 is applied a force of 60 N horizonta
krok68 [10]
Work is calculated by multiplying force by the distance that the object had moved. The applied force is 60 N, moving the object by 10 m. Thus, the work does is 600 J. For the friction force which is equal to,
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the work done is,
                        W = (60 N - 25 N) x 10 m = 350 J
The kinetic energy of the box can be equated to this force. Thus, the answer is also 350 J. 
6 0
3 years ago
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