Complete Question 
An athlete at the gym holds a 3.0 kg steel ball in his hand. His arm is 70 cm long and has a mass of 4.0 kg. Assume, a bit unrealistically, that the athlete's arm is uniform.
What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor? Include the torque due to the steel ball, as well as the torque due to the arm's weight.
Answer:
The torque is  
Explanation:
From the question we are told that 
    The mass of the steel ball is  
     The length of arm is  
     The mass of the arm is 
 Given that the arm of the athlete is uniform them the distance from the shoulder to the center of gravity of the arm is mathematically represented as 
        
=>     
   
=>     
   
Generally the magnitude of torque about the athlete shoulder is mathematically represented as 
       
=>    
=>    
 
 
        
             
        
        
        
That's false.  No medium = no sound.
        
             
        
        
        
Answer:
c. is more than that of the fluid.
Explanation:
This problem is based on the conservation of energy and the concept of thermal equilibrium

m= mass
s= specific heat
\DeltaT=change in temperature
let s1= specific heat of solid and s2= specific heat of liquid
then 
Heat lost by solid= 
Heat gained by fluid=
Now heat gained = heat lost
therefore,
1000 S_2=800 S_1
S_1=1.25 S_2
so the specific heat of solid is more than that of the fluid.