Answer:
0.3659
Explanation:
The power (p) is given as:
P = AeσT⁴
where,
A =Area
e = transmittivity
σ = Stefan-boltzmann constant
T = Temperature
since both the bulbs radiate same power
P₁ = P₂
Where, 1 denotes the bulb 1
2 denotes the bulb 2
thus,
A₁e₁σT₁⁴ = A₂e₂σT₂⁴
Now e₁=e₂
⇒A₁T₁⁴ = A₂T₂⁴
or
substituting the values in the above question we get
or
=0.3659
Answer:
Explanation:
Here two charges are placed at distance "d" apart
now the net value of electric field at some position between two charges will be ZERO
so we will have
electric field due to charge 1 = electric field due to charge 2
Let the position where net field is zero will lie at distance "r" from q1
now we will have
now square root both sides
now we have
so we have
a) , 1.6 A
b) , 1.33 A
Explanation:
a)
In this situation, we have two resistors connected in series.
The equivalent resistance of resistors in series is equal to the sum of the individual resistances, so in this circuit:
where
Therefore, the equivalent resistance is
Now we can use Ohm's Law to find the current flowing through the circuit:
where
V = 8 V is the voltage supplied by the battery
is the equivalent resistance of the circuit
Substituting,
The two resistors are connected in series, therefore the current flowing through each resistor is the same, 1.6 A.
b)
In this part, a third resistor is added in series to the circuit; so the new equivalent resistance of the circuit is
where:
Substituting, we find the equivalent resistance:
Now we can find the current through the circuit by using again Ohm's Law:
where
V = 8 V is the voltage supplied by the battery
is the equivalent resistance
Substituting,
And the three resistors are connected in series, therefore the current flowing through each resistor is the same, 1.33 A.