Artists can create emphasis in a competition using

laser light hits two very narrow slits that are separated by 0.1mm adn is viewwed on a screen 2m downstream. Sketch on the axis

Irina-Kira [14]

Answer:

d y / x = m λ

Explanation:

When the laser beam, which is a coherent light, hits the slits, part of each beam passes through each slit.

When this is observed on a screen that is quite far from the slits, a series of intense linear separated by dark areas. The explanation for this distribution of the light pattern is that when adding the rays that come out of the slits they travel different distances, which introduces a difference in optical path and if this difference is an integer multiple of the wavelength, a bright line

d sin θ = m λ

Where d is the distance between the slits (0.1 mm)

Also, since the angle of the measurements is small, we can approximate the tangent

tan θ = y / x = sin θ /sin θ

sint θ = y / x

Substituting into the equation

d y / x = m λ

This expression gives the location of the bright lines on the screen

5 0

3 years ago

Read 2 more answers

What causes the random, zig-zag movement (Brownian motion) of smoke particles suspended in air?

lidiya [134]

Answer:

It is caused by air molecules colliding with smoke particles

Explanation:

To start with, Brownian motion is the erratic or irregular movement of very small particles in a medium due to continuous bombardment by molecules that surround the medium.

Thus, smoke moves in a Zig-Zag manner (Brownian motion) due to continious air bombardment. If it were pollen grain suspended in water, the erratic movement (Brownian motion) of the grains is caused by bombardment from water molecules.

8 0

3 years ago

A truck driver is broadcasting at a frequency of 27.075 MHz with a CB (citizen's band) radio. Determine the wavelength of the el

Sergio [31]

Answer:

11m

Explanation:

Wavelength of a wave is the distance between successive crests and trough of a wave. It is represented mathematically as the ratio of the speed of the wave to its frequency. It can be expressed as;

Wavelength ¶ = wave speed (v) /frequency (f)

Given the speed of light c = 2.9979 10^8 m/s.

frequency of the radio wave = 27.075 MHz = 27.075×10^6Hz

Wavelength = 2.9979 10^8/27.075×10^6

Wavelength = 0.11×10^2

Wavelength = 11m

Therefore, the wavelength of the electromagnetic wave being used is 11m

3 0

3 years ago

I shared a picture of the problem. It’s a basic Physics question and an Algebra question.

julia-pushkina [17]

Hence the expression of ω in terms of m and k is

$\omega = \sqrt{\frac{k}{m}$

Given the expressions;

$T_s = 2 \pi \sqrt{\frac{m}{k} } \ and \ T_s = \frac{2 \pi}{\omega}$

Equating both expressions we will have;

$2 \pi \sqrt{\frac{m}{k} } = \frac{2 \pi}{\omega}$

Divide both equations by 2π

$\frac{2 \pi\sqrt{\frac{m}{2 \pi} } }{2 \pi}=\frac{\frac{2 \pi}{\omega} }{2\pi}\\\sqrt{\frac{m}{2 \pi} } = \frac{1}{\omega}\\$

Square both sides

$(\sqrt{\frac{m}{k} } )^2 = (\frac{1}{\omega} )^2\\\frac{m}{k} = \frac{1}{\omega ^2} \\\omega ^2 = \frac{k}{m}$

Take the square root of both sides

$\sqrt{\omega ^2} =\sqrt{\frac{k}{m} } \\\omega = \sqrt{\frac{k}{m}$

Hence the expression of ω in terms of m and k is

$\omega = \sqrt{\frac{k}{m}$

3 0

3 years ago

Joe is hiking through the woods when he decides to stop and take in the view. He is particularly interested in three objects: a

Novosadov [1.4K]

Answer:

A) correct answer is C, B) correct answer is b and C) The correct answer is b

Explanation:

In the exercises of geometric optics, the equation of the constructor tells us the location of the image.

1 / f = 1 / p + 1 / q

where f is the focal length of the cornea-crystalline system, p and q are the distances to the object and the image.

In this case, the distance to the image on the retina is constant, about 3 cm. Therefore depending on the distance to the object) p = the focal length must change

1 / q = 1 / f 1 / p

let's apply this expression to our case

A) indicates that the tree is at a medium distance

so that the image is formed on the retina THE SAME AS

correct answer is C

B) The squirrel is at a smaller distance (p ') than the tree (p), therefore if we substitute in the equation above we find that q must decrease. Consequently the image is in front of the retina

The mountain is very far, suppose in infinity, so the image is BEHIND THE RETINA

therefore the correct answer is b

C) The squirrel is very close so the curvature of the lens INCREASES, resulting in a DECREASE in the focal length

The correct answer is b

6 0

3 years ago