As per impulse momentum theorem we know that

now here we will have

t = 1.30 ms
m = 0.144 kg

now we need to find final speed using above formula


so final speed is given as above
 
        
             
        
        
        
Answer:
The average magnetic flux through each turn of the inner solenoid is 
Explanation:
Given that,
Number of turns = 22 turns
Number of turns another coil = 330 turns
Length of solenoid = 21.0 cm
Diameter = 2.30 cm
Current in inner solenoid = 0.140 A
Rate = 1800 A/s
Suppose For this time, calculate the average magnetic flux through each turn of the inner solenoid
We need to calculate the magnetic flux
Using formula of magnetic flux


Put the value into the formula


Hence, The average magnetic flux through each turn of the inner solenoid is 
 
        
             
        
        
        
Answer:
If excess nitrogen is found in the crop fields, the drainage water can introduce it into ... have aquifers that can supply a lot of freshwater very near the land surface. 
 
        
             
        
        
        
The volume of the balloon will halve
Explanation:
Boyle's law states that for an ideal gas kept at constant temperature, the pressure of the gas is proportional to its volume. Mathematically,

where
p is the gas pressure
V is the volume
The equation can also be rewritten as

And if we apply it to the gas inside the balloon in this problem (assuming its temperature is constant), we have:
 is the initial pressure at sea level (the atmospheric pressure)
 is the initial pressure at sea level (the atmospheric pressure)
 is the initial volume
 is the initial volume
 is the final pressure
 is the final pressure
 is the final volume
 is the final volume
Substituting into the equation, we find:

Which means that the volume of the balloon will halve.
Learn more about ideal gases:
brainly.com/question/9321544
brainly.com/question/7316997
brainly.com/question/3658563
#LearnwithBrainly
 
        
             
        
        
        
Answer:
it shows the products of a chemical reaction to the right of the reaction arrow