Mike age is 3 less then twice the age of his brother nuke.
M = Mike's age now
N = Nuke's age now
M = 2N - 3
Ten years ago, four times nuke's age was one more mike's age.
M-10 = Mike's age 10 years ago
N-10 = Muke's age 10 years ago
4(N - 10) = 1 + M -10
what are their present ages
find M and N
substitute M = 2N - 3 into 4(N - 10) = 1 + M -10:
4(N - 10) = 1 + [2N - 3] - 10
4N - 40 = 2N - 12
2N = 28
N = 14
M = 2(14) - 3 = 28 - 3 = 25
Mike is 25 and Nuke is 14.
check:
4(14 - 10) = 4(4) = 16 = 26 -10 = 1 + 25 - 10
Answer:
a.(+4) and (+2)
Mark my answere branliest thanks
To answer this, let the 3 sides of the regular sized rectangular box be x, y, and z.
When we double all the sides, the new sides have lengths 2x, 2y, and 2z, respectively.
Since the regular box (with dimensions x,y, and z) have 750 toothpicks, we can write
Similarly we can write for the jumbo box as,
which is equal to 
So this is 8 times the original of 
. Hence the jumbo box will have 8 times 750 number of toothpicks.
ANSWER: 
toothpicks
30:45
6:9
10:15
I believe that’s it,
hope this helps
