Answer:
B. 4x^2=28x-112=0.
Step-by-step explanation:
Using area=length*width, 160=(2x+8)(2x+6).
Expanding, (2x+8)(2x+6)=4x^2+16x+12x+48.
Setting this equal to 160, 160=4x^2+28x+48, or 4x^2+28x-112=0.
I have no idea what the question is so?
Let 
be the length of one leg, and 
be the length of the hypothenuse. Finally, let 
be the measure of the angle between them. Then, the following relation holds:
Plugging your values, we have
Solving for x, we have
Answer:
Jack has 10 left
Step-by-step explanation:
