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Igoryamba
3 years ago
14

Solve for x 3x + 80 = 107 What are the Awnser to these 2

Mathematics
2 answers:
kolezko [41]3 years ago
7 0

Answer:

x=9

Step-by-step explanation:

BARSIC [14]3 years ago
5 0

Answer:

for 3x+80=107,  x equals 9

For the 2=x/62, x equals 124

Step-by-step explanation:

For the first one, you would want to get x by itself so subtract 80 to the other side, which you get 27. Then you would only have 3x, so to get rid of that 3 you would divide 3 on both sides, having x=9. For the second problem you would do the opposite of dividing which is multiplying. So to get x by itself you would multiply 62 on both sides. 62 x 2 = 124. So x=124.

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elena55 [62]
2 loaves per hour and 14 loaves total in 7 hours
5 0
3 years ago
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Is the ordered pair a solution of the system? Explain with a sentence.
kotykmax [81]
It is a solution.
Explanation : 2(2)+(1)=5. (2)-(1)=1

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2 years ago
A circle in the xy-plane has its center at the point (-6,1). If the point (7, 12) lies on the circle,
Delicious77 [7]

Answer:

radius ≈ 17.0 units

Step-by-step explanation:

The radius is the distance from the centre of the circle to a point on it.

Calculate the radius r using the distance formula

r = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = (- 6, 1) and (x₂, y₂ ) = (7, 12)

r = \sqrt{(7+6)^2+(12-1)^2}

  = \sqrt{13^2+11^2}

  = \sqrt{169+121}

   = \sqrt{290} ≈ 17.0 ( to the nearest tenth )

4 0
3 years ago
23.8 is 10% of what amount​
Tju [1.3M]

10% × 23.8 =

(10 ÷ 100) × 23.8 =

(10 × 23.8) ÷ 100 =

238 ÷ 100 =

2.38

Proof

2.38 ÷ 23.8 =

0.1 =

0.1 × 100/100 =

0.1 × 100% =

(0.1 × 100)% =

10%

6 0
3 years ago
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Which ordered pairs could be points on a line parallel to the line that contains (3, 4) and (–2, 2)? Check all that apply. (–2,
Nesterboy [21]

Answer:-The required ordered pairs are (–1,1) and (–6,–1),(0, 0) and (2, 5)  and (3, 0) and (8, 2).


Explanation:-

We know that parallel lines have equal slopes.

Slope of line that contains (3,4) and (-2,2)= \frac{y_2-y_1}{x_2-x_1}=\frac{2-4}{-2-3}=\frac{2}{5}

Given options are:-

  1. Slope of line that contains (–2,–5) and (–7,–3)= \frac{-3-(-5)}{-7-(-2)}=\frac{-2}{5}
  2. Slope of line that contains (–1,1) and (–6,–1) = \frac{-1-1}{-6-(-1)}=\frac{2}{5}
  3. Slope of line that contains (0, 0) and (2, 5)= \frac{0-5}{0-2}=\frac{5}{2}
  4. Slope of line that contains (1,0) and (6,2) = \frac{2-0}{6-1}=\frac{2}{5}
  5. Slope of line that contains (3, 0) and (8, 2)= \frac{2-0}{8-3}=\frac{2}{5}

We can see Slope of line contains (–1,1) and (–6,–1), Slope of line that contains (0, 0) and (2, 5) and Slope of line that contains (3, 0) and (8, 2) have same slope as the given line.

Thus the required ordered pairs are (–1,1) and (–6,–1),(0, 0) and (2, 5)  and (3, 0) and (8, 2).

4 0
3 years ago
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