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3 years ago

A line passes through the points (-6, -3)and (6,-3) which of the following points is also on the line

Mathematics

1 answer:

vlada-n [284]3 years ago

8 0

Answer:

SEND YOUR LOCATION COME THROUGH you a rear breed no comparing

Step-by-step explanation:

You might be interested in

Renee was able to plant 15 plant in 5min at this rate how many flowers could she paint plant in 45 min

Sedbober [7]

Answer:

Answer is 135 plant

Step-by-step explanation:

We have given that,

In 5 min Renee can plant 15 plant.

That means in one minute Renee can plant $\frac{15}{5}$ plant.

i.e. Rate of planting = 3 plant per minute

So, In 45 minutes , she can plant 45×3 plant

i.e Plant she can plant in 45 minute = 135 plant

6 0

3 years ago

If 3x is the opposite of -5, what is the value of x?<br> -3<br> 5<br> 5/3<br> -1/15

Leokris [45]

The Value of X is 5 is the answer

5 0

2 years ago

The average score of students in Mr. Blake's science class was 73 with a standard deviation of 11, while the average score of st

Pani-rosa [81]

Answer:

Mr Blake's science class

Step-by-step explanation:

The standard deviation is a measure of variation.

It tells us how far each of the data set in the distribution are far from the mean of the distribution.

The average score of students in Mr. Blake's science class was 73 with a standard deviation of 11, while the average score of students in Mrs. Arnold's class was 75 with a standard deviation of 10.

Since 11>10, Mr Blake's science class is more variable than Mrs. Arnold's class.

3 0

2 years ago

How many cubic feet of water will it take to fill a pool that measures 25 feet by 22 feet by 4 feet?

Akimi4 [234]

Answer:

2200 cubic feet of water

Step-by-step explanation:

25x22x4=2200

3 0

3 years ago

Read 2 more answers

The Identity function i behaves just like the number 1. That is (F o i)=f and (i o g)= g

andrezito [222]

I'll denote the identity function by $\mathrm{Id}$ . Then for any functions $f$ with inverse $f^{-1}$ ,

$\begin{cases}f\circ\mathrm{Id}=f\\\mathrm{Id}\circ f=f\\f\circ f^{-1}=\mathrm{Id}\end{cases}$

One important fact is that composition is associative, meaning for functions $f,g,h$ , we have

$(f\circ g)\circ h=f\circ(g\circ h)$

So given

$h=f\circ g$

we can compose the functions on either side with $g^{-1}$ :

$h\circ g^{-1}=(f\circ g)\circ g^{-1}=f\circ(g\circ g^{-1})$

then apply the rules listed above:

$h\circ g^{-1}=f\circ\mathrm{Id}=f$

3 0

3 years ago