Question

Solve the following quadratic equation by using the quadratic formula.

Answer 1

Answer:

B. $\frac{-3}{4}$±$\frac{\sqrt{41} }{4}$

Step-by-step explanation:

First, substitute the equation into the quadratic formula.

$x=\frac{b+-\sqrt{(b^{2} )-4(a)(c)} }{2a}$

x=$\frac{-3+-\sqrt{(3)^2-4(-2)(4)} }{4}$

Solve for x.

x= $\frac{-3+-\sqrt{9+32} }{4}$

x=$\frac{-3+-\sqrt{41} }{4}$

The answer is x= $-\frac{3}{4}$±$\frac{\sqrt{41} }{4}$