Answer:
Step-by-step explanation:
To find the distance between two points, 
and 
, you can use the following distance formula:
Plugging in the points from the problem, you'll get the following:
8.373 rounded to the nearest hundredth is 8.37 because you look at the thousandths place or to the right of 7 and you see that its lower than 5 so you round down giving you the answer of 8.73
Answer: 8.73
<u>Answer </u><u>:</u>
In the given quadrilateral ABCD ,
- Angle BCA = 18°
- Angle ACD = 62°
Angle BCA = Angle CAD ( alternate interior angle )
Now in triangle CAD ,
We have two angles so by using angle sum property we can find the required third one ,
- Angle CAD + Angle ACD + Angle ADC = 180°
- 18 + 62 + Angle ADC = 180
- 80 + Angle ADC = 180
- Angle ADC = 180 - 80
- Angle ADC = 100
–2a² + 4ab – 5a – 2b + b²
Solution:
Given data:
–2a(a + b – 5) + 3(–5a + 2b) + b(6a + b – 8)
<u>To solve this expression:</u>
Multiply each number or variable into the bracket.
–2a(a + b – 5) + 3(–5a + 2b) + b(6a + b – 8)
= –2a² – 2ab + 10a – 15a + 6b + 6ab + b² – 8b
Arrange like terms together.
= –2a² – 2ab + 6ab + 10a – 15a + 6b – 8b + b²
= –2a² + 4ab – 5a – 2b + b²
Hence the solution is –2a² + 4ab – 5a – 2b + b².
Answer:
(4, -3)
Step-by-step explanation:
To solve this with graphing all you need to do is enter both equations in a graphing calculator (you can use desmos online) and then find the point where both lines intersect.
