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Nostrana [21]
3 years ago
15

When the reddish-brown mercury(ii) oxide (hgo) is heated, it decomposes to its elements, liquid mercury metal and oxygen gas. if

1.19 g hgo is decomposed to hg, calculate the mass of the pure hg metal produced. 2 hgo(s) 2 hg(l) + o2(g)?
Chemistry
1 answer:
konstantin123 [22]3 years ago
7 0
2HgO----->  2Hg  +  O2

find  the  moles  of  HgO,

moles=mass/molar  mass

1.19g/216.59(molar  mass  of  HgO) =   5.49  x10^-3moles

by  use   of  mole  ratio  between  HgO  and Hg  which  is  2:2    or  1:1  the moles   of  Hg  is  also   5.49  x10^-3  moles

mass  of  Hg  is  therefore  =  (5.49  x10^-3)  x  200.59  =  1.101  grams
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The air at the top of Mount Everest has pressures of 201.0 torr N2, 50.0 torr O2, 2.0 torr Ar, and 0.5 torr CO2. What is the tot
nordsb [41]

Answer:

The total air pressure at the top of the highest peak in the world is 253.5 torr

Explanation:

The partial pressures of the gases present at the top of Mount Everest are;

Nitrogen, N₂ = 201.0 torr

Oxygen, O₂ = 50.0 torr

Argon, Ar = 2.0 torr

Carbon dioxide, CO₂ = 0.5 torr

By Dalton's law of partial pressure, the total pressure that a mixture of gases exerts is equal to the sum of the partial pressures of the individual gases

Mathematically, the law can be expressed as follows;

Total pressure, P = ∑P_i = P₁ + P₂ + · · ·

From which we have;

The total air pressure at the top of the highest peak in the world, Mount Everest, P_{Total Mont Everest} = The sum of the partial pressures of N₂, O₂, Ar, and CO₂

P_{Total Mont Everest} = 201.0 torr + 50.0 torr + 2.0 torr + 0.5 torr = 253.5 torr

P_{Total Mont Everest} = 253.5 torr = 0.33355263 atmosphere

Therefore, the total air pressure at the top of the highest peak in the world,  P_{Total Mont Everest} = 253.5 torr

3 0
2 years ago
A positron is emitted when ____________. *
Darina [25.2K]
The correct answer is:
a positron is emitted when proton converts to a neutron.

The reaction can be described as following:
₁¹p (proton) → ₀¹n (neutron) + ₁°e (positron or ₁⁰β)
Positron is an antiparticle of a β particle (₋₁°β), which means it has an oposite charge to it, but same mass.

7 0
3 years ago
The ammonia molecule NH3 has a permanent electric dipole moment equal to 1.47 D, where 1 D = 1 debye unit = 3.34 × 10-30 C-m. Ca
svetoff [14.1K]

The electric potential due to ammonia at a point away along the axis of a dipole is 1.44 \times 10^-5 V.

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Given that 1 D = 1 debye unit = 3.34 × 10-30 C-m.

Given p = 1.47 D = 1.47 \times 3.34 \times 10^-30 = 4.90 \times 10^-30.

            V = 1 / (4π∈о)  \times  (p cos(θ)) / (r^2)

where p is a permanent electric dipole,

           ∈ο is permittivity,

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            V is the electric potential.

        V = 1 / (4 \times 3.14 \times 8.85 \times 10^-12)  \times (4.90 \times 10^-30 \times 1) / (55.3 \times 10^-9)^2

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