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Likurg_2 [28]
3 years ago
10

Which Triangles are congruent by ASA

Mathematics
2 answers:
PolarNik [594]3 years ago
8 0
Triangles congruent by ASA have two pairs of congruent sides and an included congruent angle.

The graph indicates that sides TV, HG, and AB are congruent, and that sides TU, FG, and BC are congruent. It also indicates that angles U, F, and C are congruent, and that angles G and B are congruent. Notice that angle U of  triangle TUV is not an included angle; this eliminates triangle TUV as it can't be congruent to another triangle by ASA with the information provided.

That leaves triangles FGH and ABC. Evidently, angles G and B are included angles, so these triangles are congruent by ASA.

Answer:
b. ΔHGF and ΔABC
sweet-ann [11.9K]3 years ago
6 0

Answer:

b.\triangle HGF\cong \triangle ABC

Step-by-step explanation:

We are given that three triangles VTU,HGF and ABC.

We have to find the triangle which are congruent by ASA.

ASA postulate: When two angles of one triangle and side on which two equal angles  are made are congruent to its corresponding two angles and corresponding side of other triangle then, two triangles are congruent by ASA.

From given figure, we can see that

AB=HG=VT

BC=FG=TU

\angle V=\angle F=\angle C

\angle G=\angle B

Therefore, \triangle HGF\cong \triangle ABC

By ASA postulate because two angle of triangle HGF angle F and angle G and one side FG are congruent to corresponding angles C and B and corresponding side BC.

Option b is true.

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36

I hope this helps


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Each of these extreme value problems has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to f
tino4ka555 [31]

Answer:

The minimum value of the given function is f(0) = 0

Step-by-step explanation:

Explanation:-

Extreme value :-  f(a, b) is said to be an extreme value of given function 'f' , if it is a maximum or minimum value.

i) the necessary and sufficient condition for f(x)  to have a maximum or minimum at given point.

ii)  find first derivative f^{l} (x) and equating zero

iii) solve and find 'x' values

iv) Find second derivative f^{ll}(x) >0 then find the minimum value at x=a

v) Find second derivative f^{ll}(x) then find the maximum value at x=a

Problem:-

Given function is f(x) = log ( x^2 +1)

<u>step1:</u>- find first derivative f^{l} (x) and equating zero

  f^{l}(x) = \frac{1}{x^2+1} \frac{d}{dx}(x^2+1)

f^{l}(x) = \frac{1}{x^2+1} (2x)  ……………(1)

f^{l}(x) = \frac{1}{x^2+1} (2x)=0

the point is x=0

<u>step2:-</u>

Again differentiating with respective to 'x', we get

f^{ll}(x)=\frac{x^2+1(2)-2x(2x)}{(x^2+1)^2}

on simplification , we get

f^{ll}(x) = \frac{-2x^2+2}{(x^2+1)^2}

put x= 0 we get f^{ll}(0) = \frac{2}{(1)^2}   > 0

f^{ll}(x) >0 then find the minimum value at x=0

<u>Final answer</u>:-

The minimum value of the given function is f(0) = 0

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tangare [24]

Answer:

D)$42.00

Step-by-step explanation:

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