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LuckyWell [14K]
2 years ago
9

Which of the following is algebraically equivalent to the sum of and ?

Mathematics
1 answer:
Naddika [18.5K]2 years ago
4 0

What is the question marks value?

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8 3/5 - 1 3/10 = ?<br><br> this is fractions
Semenov [28]
1)  8 \frac{3}{5} - 1 \frac{3}{10}

2)  8 \frac{6}{10} - 1 \frac{3}{10}=

3)  7\frac{3}{10}

Answer
7 \frac{3}{10}
4 0
3 years ago
Read 2 more answers
Which value of c would make the following express completely factored? 8x+cy
Artist 52 [7]
The answer is B, 7.

\sf 8x+2y

We can factor a 2 out of this: \sf 2(4x+y)

\boxed{\sf 8x+7y}

We can't factor anything.

\sf 8x+12y

We can factor a 4 out of this: \sf 4(2x+3y)

\sf 8x+16y

We can factor an 8 out of this: \sf 8(x+2y)

So your answer is B, 7.
6 0
3 years ago
Read 2 more answers
Write an equation in slope-intercept
Sliva [168]
Y= 1x + 2

Use the formula y=mx+b when trying to do things like this.
Y intercept form is when your line intersects through the y axis, and this is also your b. M is your slope.
7 0
3 years ago
Determine if the graph is symmetric about the x-axis, the y-axis, or the origin. r = 5 cos 3θ
Aneli [31]
First of all get a picture of what this looks like. Desmos is a pretty good graphing program, but anything that will do polar coordinates will work. 

Here is the graph.

What you can see is that this graph is symmetrical around the x axis.

When you talk about symmetry, you can think of it as taking a mirror and putting it where you think there is symmetry. If you can't tell the difference between the image and the real thing, then you have symmetry.

In this case, the mirror will show symmetry along the x axis and no where else.

4 0
3 years ago
Read 2 more answers
Find the lateral area of the cylinder. Give your answer in terms of pi
Artist 52 [7]

Answer:

<h2>204π units²</h2>

Step-by-step explanation:

The lateral area of the cylinder includes both the side and the ends.

The area of the side can be found by calculating the circumference of the cylinder and multiplying that by the height:  A = 2π(6 units )(11 units) = 132π units².

The area of one end of this cylinder can be found by applying the "area of a circle" formula:  A = πr².  Here, with r = 6 units, A = π(6 units)² = 36π units².  Since the cylinder has two ends, the total area of the ends is thus 2(36π units) = 72π units.

The total lateral area of the cylinder is thus 72π units² + 132π units², or 204π units²

7 0
3 years ago
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