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Gwar [14]
3 years ago
15

A cable company charges a monthly fee for cable service plus an additional $3 for each premium channel. This is given by the fun

ction y = 3x + 28.5. George has cable service with 4 premium channels. Write the domain and range using set notation. What is the cost of George’s monthly cable service?
Mathematics
1 answer:
svlad2 [7]3 years ago
3 0

Answer:

domain all real numbers

range all real numbers

the cost of his monthly cable is $40.50 when you plug in 4

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aleksklad [387]

I can try to do my best

may i also receive brainliest on this one as well please?

4 0
3 years ago
There were a total of 61,069,054 votes for the winner in the 2004 presidential election.
d1i1m1o1n [39]
6 is in the ten millions place. The number next to 6 is 1, which is less than 5, so you round down. The nearest 10 million is 60,000,000.
8 0
2 years ago
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Line ab contains the points a(-2,3) and b(4,5). Line ab has a slope that is
gayaneshka [121]

Given two points A = (A_x, A_y),\ B = (B_x,B_y), the slope of the line passing through the two points is

m = \dfrac{A_y-B_y}{A_x-B_x}

So, in your case, you have

m = \dfrac{3-5}{-2-4} = \dfrac{-2}{-6} = \dfrac{1}{3}

5 0
3 years ago
Es 18 de junio de 1815, las tropas napoleónicas se encuentran justo adelante, tu eres el ingeniero en balística y el general Wel
Airida [17]

Answer:

89.1° or -1.4°  

Step-by-step explanation:

1. Location:

You are on the Mont-Saint-Jean escarpment, near the Belgian town of Waterloo.

The French troops are about 50 m below you and 1.2 km distant.

2. Finding the firing angle

Data:

R = 1200 m

u = 600 m/s

h = -50 m (the height of the target)

a = 9.8 m/s²

We have two conditions.

Horizontal distance

(1) 1200 = 600t cosθ

Vertical distance

(2) -50 = 600t sinθ - 4.9t²

Divide each side of (1) by 600cosθ.

(3) \, t =\dfrac{2}{\cos \theta}

Substitute (3) into (2)

-50 = 600t \sin \theta - 4.9t^{2} =  600 \left( \dfrac{2}{\cos \theta} \right ) \sin \theta - 4.9 \left( \dfrac{2}{\cos \theta} \right )^{2}\\\\(4) \, -50 = 1200 \tan \theta - \dfrac{19.6}{\cos^{2} \theta}

Recall that

(5) sec²θ = 1/cos²θ = tan²θ + 1

Substitute (5) into (4)

-50 = 1200 \tan \theta - 19.6 \left(\tan^{2} \theta}+ 1\right )

Set up a quadratic equation

\begin{array}{rcl}-50 & = & 1200 \tan \theta - 19.6\tan^{2} \theta -19.6 \\0 & = & 1200 \tan \theta - 19.6\tan^{2} \theta + 30.4\\0 & =&19.6\tan^{2} \theta - 1200 \tan \theta - 30.4\\0 & =&\tan^{2} \theta - 61.224 \tan \theta - 1.551\\\end{array}

Solve for θ

Use the quadratic formula.

tanθ = 61.249 or -0.025

θ = arctan(61.249) = 89.1° or

θ = arctan(-0.025) = -1.4°

3 0
3 years ago
61/2×(8/9÷13/18)+(3/4) of 31/5​
liberstina [14]

Answer:

\frac{10969}{260}

Step-by-step explanation:

8 0
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