Let's assume the opposite is the case. So let's assume that a = b is true. If so, then f(a) and f(b) would be the same output. This is because we can replace 'b' with 'a', or vice versa. In other words, f(a) = f(b) would be true. But this contradicts the original inequality that f(b) < f(a)
So that is why 'a' cannot equal b. We don't know if a > b or if a < b (unless we are told if the function is strictly decreasing or increasing on the interval from x = a to x = b), so we just leave it as 
Answer:
the correct answer are the last three options
Step-by-step explanation:
i just took the test and got it right
Answer:Partial quotients Paloma should show in her work are B) 30,10,1.
Step-by-step explanation:
Given : Paloma dividing 1292 (dividend) by 31 (divisor) using partial quotients.
so the easy multiples of 31 are as 31×2=62 ,31×3=93,31×10=310....so on
if she uses 30 as her first partial quotient then 31×30=930, so after subtracting 930 from 1292 we get 362 as new dividend then 31×10=310 is the easiest multiple of 31 so that 362-310=52 as new dividend ,then 31×1=31 subtracting this from 52 gives 52-31=21 which is the remainder.
Therefore, Partial quotients Paloma should show in her work are 30,10 and 1.
Answer:
5
Step-by-step explanation:
