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Lady bird [3.3K]
3 years ago
12

Directions: Directions: Identify x1, x2, y1, and y2. Solve for the of the line passing through the given points. Identify if the

slope is positive, negative, zero, or undefined.
1.​(2,1) and (5,3)
2.​(-2,1) and (1, -3)
3.​(4,1) and (5,1)
4.​(7,-1) and (7,5)
5.​(-2,1) and (3,6)​
Mathematics
2 answers:
Arlecino [84]3 years ago
8 0

Answer:

Remember you are just a normal account

anygoal [31]3 years ago
4 0

Step-by-step explanation:

Number 1

m = (y2 - y1)/(x2 - x1)

m = (3 - 1)/(5 - 2)

m = 2/3 POSITIVE

Number 2

m = (y2 - y1)/(x2 - x1)

m = (-3 - 1)/(1 + 2)

m = -4/3 NEGATIVE

Number 3

m = (y2 - y1)/(x2 - x1)

m = (1 - 1)/(5 - 4)

m = 0/1

m = 0 ZERO

Number 4

m = (y2 - y1)/(x2 - x1)

m = (5 - 1)/(7 - 7)

m = 4/0

m = UNDEFINED

Number 5

m = (y2 - y1)/(x2 - x1)

m = (6 - 1)/(3 + 2)

m = 5/5

m = 1 POSITIVE

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2 years ago
Which is the correct way to solve the given equation
Karolina [17]

Option 2. x = \frac{4 \pm \sqrt{(-4)^{2}-4 (1)(-21)}}{2 (1)} shows the correct way to use the quadratic formula to solve the given equation.

Step-by-step explanation:

Step 1:

For an equation of the form ax^{2} +bx+c=0 the solution is x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}.

Here a is the coefficient of x^{2}, b is the coefficient of x and c is the constant term.

x^{2} -4x=21 can also be written as x^{2} -4x-21=0.

Comparing x^{2} -4x-21=0 with ax^{2} +bx+c=0, we get that a is 1, b is -4 and c is -21.

To get the solution, we substitute the values of a, b, and c in x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}.

Step 2:

Substituting the values, we get

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This is option 2.

7 0
4 years ago
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