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Lady bird [3.3K]
3 years ago
12

Directions: Directions: Identify x1, x2, y1, and y2. Solve for the of the line passing through the given points. Identify if the

slope is positive, negative, zero, or undefined.
1.​(2,1) and (5,3)
2.​(-2,1) and (1, -3)
3.​(4,1) and (5,1)
4.​(7,-1) and (7,5)
5.​(-2,1) and (3,6)​
Mathematics
2 answers:
Arlecino [84]3 years ago
8 0

Answer:

Remember you are just a normal account

anygoal [31]3 years ago
4 0

Step-by-step explanation:

Number 1

m = (y2 - y1)/(x2 - x1)

m = (3 - 1)/(5 - 2)

m = 2/3 POSITIVE

Number 2

m = (y2 - y1)/(x2 - x1)

m = (-3 - 1)/(1 + 2)

m = -4/3 NEGATIVE

Number 3

m = (y2 - y1)/(x2 - x1)

m = (1 - 1)/(5 - 4)

m = 0/1

m = 0 ZERO

Number 4

m = (y2 - y1)/(x2 - x1)

m = (5 - 1)/(7 - 7)

m = 4/0

m = UNDEFINED

Number 5

m = (y2 - y1)/(x2 - x1)

m = (6 - 1)/(3 + 2)

m = 5/5

m = 1 POSITIVE

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Nataly_w [17]

Answer:

Option a) 1/5 is most closely to 0.

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2 years ago
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What is the product in simplest form x^2+9x+18/x+2 times x^2-3x-10/x^2+2x-24
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\dfrac{x^2+9x+18}{x+2}\cdot\dfrac{x^2-3x-10}{x^2+2x-24}=\dfrac{x^2+6x+3x+18}{x+2}\cdot\dfrac{x^2-5x+2x-10}{x^2+6x-4x-24}\\\\=\dfrac{x(x+6)+3(x+6)}{x+2}\cdot\dfrac{x(x-5)+2(x-5)}{x(x+6)-4(x+6)}

=\dfrac{(x+6)(x+3)}{x+2}\cdot\dfrac{(x-5)(x+2)}{(x+6)(x-4)}=\dfrac{(x+3)(x-5)}{x-4}\\\\=\dfrac{x^2-5x+3x-15}{x-4}=\dfrac{x^2-2x-15}{x-4}
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Draw an angle of 40 degree. copy it's supplementary angle
Mila [183]
This is the correct form of a supplementary angle. 

3 0
3 years ago
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stiv31 [10]

Answer:

A

Step-by-step explanation:

Hello There!

The y value of ABC was subtracted by 7 to get to the figure A'B'C'

So the rule for the given transformation would be

(x,y) ---> (x,y-7)

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Graph ​ y+6=45(x+3) ​ using the point and slope given in the equation
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Step-by-step explanation:

We have been given an equation y+6=45(x+3) in point slope form.

It says to use the point and slope from given equation to create the graph.

So compare equation y+6=45(x+3) with point slope formula

y-y1=m(x-x1)

we see that m=45, x1=-3 and y1=-6

Hence first point is at (-3,-6)

slope m=45 is positive so to find another point, previous point will move 45 units up then 1 unit right and reach at the location (-2,39).

Now we just graph both points (-3,-6) and  (-2,39) and join them by a straight line. Final graph will look like the attached graph.

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3 years ago
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