If y varies directly as x, and y is 20 when x is 4, what is the constant of variation for this relation?
2 answers:
Answer: 5
Step-by-step explanation:
Let k be the constant of variation for this relation.
If y varies directly as x, then the equation of direct variation is given by ;-
, where k is the constant of variation for the relation.
Now, for the given value of y = 20 and x=4, the value of constant of variation is given by :-
Hence, the value of constant of variation for this relation k = 5.
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Answer:
Area the figure = 45 - 9 = 36 units² ⇒ last answer
Step-by-step explanation:
<em>"I have added screenshot of the complete question as well as the diagram"</em>
All the angles of the figure are right angles
<u>From the attached figure:</u> <em>we can find the area of the figure by subtracting the area of the cutting part from the area of the rectangle of dimensions 9 units and 5 units</em>
∵ All the angles of the figure are right angles
∴ We can consider that the figure of dimensions 9 units and 5 units
as a rectangle
∵ Area of any rectangle A = L × H , where L, H are the dimensions
of the rectangle
∵ L = 9 units and H = 5 units
∴ Area of the rectangle = 9 × 5 = 45 units²
- The dimensions of the cutting part are 3 units and
[9 - (2 + 4) = 9 - 6 = 3 units]
∴ The cutting part is a square
∵ Area any square = S², where S is the length of the side of the square
∵ S = 3 units
∴ The area of the cutting part = 3² = 9 units²
∵ Area of the figure = area rectangle - area square
∵ Area the rectangle = 45 units²
∴ Area the square = 9 unit²
∴ Area the figure = 45 - 9 = 36 units²
