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Sonja [21]
2 years ago
15

Which One is GREATER 2 to the power of 7 or 7 to the power of 2

Mathematics
1 answer:
nignag [31]2 years ago
5 0

Answer:

2 to the power of 7

Step-by-step explanation:

7 to the power of 2 is 49

2 to the power of 7 is 128

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What is the perimeter?<br> Help plz....And no links!! I repeat No links!!!
Nana76 [90]

Answer:

48 cm

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
POS
meriva

Answer:

0.08 = 8%

2.3= 230%

0.34= 34%

1.05= 105%

0.7= 70%

0.049= 4.9%

7 0
3 years ago
Find three consecutive ODD integers such that the sum of 7 times the smallest and twice the largest is -91. Name the smallest in
Illusion [34]

Answer:

<h3>               -11, -9, -7</h3><h3>the smallest:   2x+1 = -11</h3>

Step-by-step explanation:

{z - some integer}

2z+1  - the smallest number

7(2z+1)  - <u>seven times the smallest number</u>

2z+1+2=2z+3  - the middle number

2z+3+2 = 2z+5 - the largest number

2(2z+5) - <u>twice the largest number</u>

7(2z+1) + 2(2z+5)  - the sum of 7 times the smallest and twice the largest

7(2z+1) + 2(2z+5)   = -91

14z + 7 + 4z + 10 = -91

              -17              -17

      18z   = -108

       ÷18        ÷18

        z = -6

2z+1 = 2(-6)+1 = -12 + 1 = -11  

2z+3 = 2(-6)+3 = -12 + 3 = -9

2z+5 = 2(-6)+5 = -12 + 5 = -7        

5 0
3 years ago
Which expression could represent the phrase shown? (1 point)
ivolga24 [154]

Answer:

(6 - 2) / 3

Step-by-step explanation:

First, use parenthesis to declare that whatever is inside will be done first. This is saying to subtract 2 from 6. Next, add / 3 after to show you are dividing the answer of 6-2 by 3.

4 0
2 years ago
Let A and B be two sets. For each of the following equalities, say whether the quality is always true, never true, or sometimes
lions [1.4K]

Answer:

hello your question is incomplete below is the missing parts

(a) A\ (A\B) = B\(B\A)

(b) A\ (BA) = B\(A\B)

answer : A\ (A\B) = B\(B\A) = always true

               A\ (BA) = B\(A\B) = sometimes true and sometimes false

Step-by-step explanation:

(a) A\ (A\B) = B\(B\A). = ALWAYS TRUE

using de Morgan's law to prove this

A\ (A\B) = A\ ( A ∩ B^c )

             = A ∩ ( A^C ∪ B )

             = ( A ∩ A^C ) ∪ ( A ∩ B )

             = Ф ∪ ( A ∩ B )

             = ( A ∩ B )

ALSO : B\(B\A) = attached below is the remaining parts of the solution

B) A\ (BA) = B\(A\B) = Sometimes true and sometimes false

attached below is the prove using De Morgan's law

8 0
3 years ago
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