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Sonja [21]
3 years ago
15

Which One is GREATER 2 to the power of 7 or 7 to the power of 2

Mathematics
1 answer:
nignag [31]3 years ago
5 0

Answer:

2 to the power of 7

Step-by-step explanation:

7 to the power of 2 is 49

2 to the power of 7 is 128

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mr. huber bought a block of fudge that weighed 2/5 of a pound. he cut the fudge into 6 equal pieces. what was the weight of each
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Answer:

\large \boxed{\frac{1}{15} \text{ lb}}

Step-by-step explanation:

You are starting with ⅖ lb of fudge. Then you cut it into six pieces.

You want to evaluate ⅖ ÷ 6

1. Treat the integer as a fraction

\dfrac{2}{5}\div{\dfrac{6}{1}}

2. Invert the divisor and change divide to multiply

\dfrac{2}{5}\times{\dfrac{1}{6}}

3. Divide numerator and denominator by 2

\dfrac{1}{5}\times{\dfrac{1}{3}}

4. Multiply numerators and denominators

\dfrac{1}{5}\times{\dfrac{1}{3}} = \mathbf{\dfrac{1}{15}}\\\\\text{Each piece of fudge weighs $\large \boxed{\mathbf{\frac{1}{15}} \textbf{ lb}}$}

7 0
4 years ago
The u.s. department of health and human services collected sample data for 772 males between the ages of 18 and 24. that sample
soldier1979 [14.2K]
The 99% confidence interval for the true mean is given by:

\bar{x}\pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}

where: 

\bar{x} is the sample mean = 69.7
\sigma is the standard deviation = 2.8
z_{\alpha/2} is the test statistics = 2.58 for for 99% confidentce interval.
n is the sample size = 772.

Therefore, the 99% confidence interval is:

69.7\pm2.58\left( \frac{2.8}{\sqrt{772}} \right)=69.7\pm2.58(0.1008) \\  \\ =69.7-0.26\leq\mu\leq69.7+0.26 \\  \\ =69.44\leq\mu\leq69.96
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Sphinxa [80]

Answer:

Vertices: (1,-1), (-11, -1); Foci: (-15, -1), (5, -1)

Step-by-step explanation:

Center at (-5,-1) because of the plus 5 added to the x and the plus 1 added to the y.

a(squared)=36 which means a=6 and a=distance from center to vertices so add and subtract 6 from the x coordinate since this is a horizontal hyperbola, which is (1,-1), (-11,-1). From there you dont need to find the focus since there is only one option for this;

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