Answer:
-270-180w
Step-by-step explanation:
"Two thirds times one half"
Step-by-step explanation:
a) mode = 3 ( cause most number of car that have 3 teachers)
b) median = 3 (1,1,1,2,2,2,2,3,3,3,3,3,3,4,4) the middle position)
c) mean = (1*3 + 2*4 +3*6 + 4*2)/15 = 2.467(average)
Answer:
1) Inequality: 110x>150+85x
2) Solution: x>6, then Nadia would need to sell more than 6 ads per week in order for Choice A to be the better choice,
<u>Solution:</u>
Be x the number of ads Nadia sells
A) Choice A: $110 for each ad she sells. She would earn:
Ea=110x
B) Choice B: A weekly salary of $150, plus $85 for each ad she sells. She would earn:
Eb=150+85x
1) Write an inequality to determine the number of ads Nadia would need to seel per week in order for Choice A to be the better choice:
Ea>Eb
110x>150+85x
2) Solution
Solving for x: Subtracting 85x both sides of the equation:
110x-85x>150+85x-85x
Subtracting:
25x>150
Dividing both sides of the equation by 25:
25x/25>150/25
Dividing:
x>6
Answer:
Cost of small box = $13
Cost of large box = $18
Step-by-step explanation:
Let the cost of small box of candy = $s
And the cost of large candy box = $b
Beth sold 9 small and 10 large boxes of candies for $297.
9s + 10b = 297 -----(1)
Sarah sold 8 small and 5 large boxes of candies for $194.
8s + 5b = 194 -------(2)
Multiply equation (2) by 2 then subtract equation (1) from (2).
2(8s + 5b) - (9s + 10b) = (2×194) - 297
16s + 10b - 9s - 10b = 388 - 297
7s = 91 ⇒ s = $13
From equation (2),
(8×13) + 5b = 194
104 + 5b = 194
5b = 90
b = $18
