The fundamental frequency of a standing wave which has
string of length L
mass per unit meu
has the tension T
is given by f = 1/2L
Now we are required to find if the tension is doubled, with all other factors held constant, what will be the effect on the fundamental frequency
According to the formula,
the fundamental frequency f is directly proportional to the factor of square root
Hence when the tension is doubled while other factors remaining constant
the formula will become
f= 1/2L
Hence the change in the fundamental frequency will be of the factor
Therefore, the change will be of
Disclaimer: the question has missing part 1 and part 2 and hence part 3 has been answered
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Answer:
3.33 m/s²
Explanation:
If the acceleration is constant, it is equal to the average acceleration:
a = Δv / Δt
First, convert km/hr to m/s:
300 km/hr × (1 hr / 3600 s) × (1000 m/km) = 83.33 m/s
a = (83.33 m/s − 0 m/s) / 25 s
a = 3.33 m/s²
The distance between Earth and Sun is about 0.0000038 times
the distance to the next nearest star.
(The next nearest star is about 265,300 times as far from us as
the sun is.)
The distance between Earth and Sun is about 0.000000000000000000068
times the distance to the next nearest galaxy.
(The next nearest galaxy is about 14,700,000,000,000,000,000 times
as far from us as the sun is.)
71% of the earth is water
You will need to convert the diameter to radius. 3840km diameter will be 1740km radius.
<span>4 x 3.1416 x 1740² = ~38,046,032km² surface area.</span>