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larisa [96]
3 years ago
12

Which two segments have the same length?

Mathematics
2 answers:
Natasha2012 [34]3 years ago
6 0

Answer: VW & YZ

Step-by-step explanation:

VW = 8

WX = 5

XY = 7

YZ = 8

Your looking for the same length so it all comes down to which two are equal.

Wittaler [7]3 years ago
3 0

it’s clearly C i can’t believe you wasted 10 points on this obvious question

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I think  you can put bench mark place valie round tenth thousnadth
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3 years ago
Perform the indicated operation.(3/a+2) + (4/a-5)
kipiarov [429]

Answer:

\frac{7(a-1)}{(a+2)(a-5)}

Step-by-step explanation:

To solve this operation we need to find the common multiple of both denominators and solve for a.

\frac{3}{a+2} + \frac{4}{a-5} =\frac{3(a-5)+4(a+2)}{(a+2)(a-5)} =\frac{3a-15+4a+8}{(a+2)(a-5)} =\frac{7a-7}{(a+2)(a-5)} =\frac{7(a-1)}{(a+2)(a-5)}

Thus, the solution is 7(a -1) / (a+2)(a-5)

8 0
3 years ago
1/2x-2 <br> One half multiply negative 2
sattari [20]

Answer:

Step-by-step explanation:

11

5 0
3 years ago
Read 2 more answers
Im having trouble figuring out the missing length and solving this, can I have some help?
belka [17]
I think the answer is 17
8 0
2 years ago
Assume that when Human Resource managers are randomly selected, 62% say job applicants should follow up within two weeks. If 25
Alenkinab [10]

Using the binomial distribution, it is found that there is a 38% probability that exactly 18 of them say job applicants should follow up within two weeks.

<h3>How to find that a given condition can be modelled by binomial distribution?</h3>

Binomial distributions consists of n independent Bernoulli trials.

Bernoulli trials are those trials that end up randomly either on success (with probability p) or on failures( with probability 1- p = q (say))

The probability that out of n trials, there'd be x successes is given by

P(X =x) = \: ^nC_xp^x(1-p)^{n-x}

Binomial probability distribution  

P(X =x) = \: ^nC_xp^x(1-p)^{n-x}

The parameters are:

n is the number of trials.

x is the number of successes.

p is the probability of success on a single trial.

In this problem:

62% say job applicants should follow up within two weeks, p = 0.62

25 managers are selected, n = 25

The probability that exactly 18 of them say job applicants should follow up within two weeks is P ( X = 18)

P( X > 18) = 1 -  ( X = 18)

= 1 - 0.62

= 0.38

38 % probability that exactly 18 of them say job applicants should follow up within two weeks.

Learn more about binomial distribution here:

brainly.com/question/13609688

#SPJ1

8 0
2 years ago
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