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sattari [20]
3 years ago
7

Pls help i need this answered asap i am giving 40 points

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
8 0

Answer:

the answer is D

Step-by-step explanation:

I hope it's right

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SOMEONE PLEASE HELP I WILL MARK U BRAINLIST
mash [69]

Answer:

x = 3

Step-by-step explanation:

In\: \triangle PQT,\: \overline{PQ}|| \overline {RS}...(Given)\\\\\implies\frac{PS}{ST}=\frac{QR}{RT}\\(By\: Proportionality\: Theorem) \\ \\\implies\frac{2x+4}{5}=\frac{3x+5}{7}\\\\ \implies \: 7(2x + 4) = 5(3x + 5) \\  \\ \implies \:14x + 28 = 15x + 25 \\  \\ 14x - 15x = 25 - 28 \\ \\ - x =  - 3 \\  \\ x = 3

7 0
2 years ago
The sum of two numbers is 41. The larger number is one less than twice the smaller number. Find the numbers.
Arte-miy333 [17]
I hope this helps you



small a

larger 2a-1


a+2a-1=41


3a=42


a=14

2a-1=2.14-1=27
6 0
3 years ago
Which shows one way to determine the factors of 12x3 – 2x2 + 18x – 3 by grouping?
Debora [2.8K]

Option A

2x^2(6x-1) + 3(6x-1) is one way to determine the factors of 12x^3-2x^2+18x-3 by grouping

<em><u>Solution:</u></em>

Factoring by grouping means that you will group terms with common factors before factoring

<em><u>Given expression is:</u></em>

12x^3-2x^2+18x-3

Group the first two terms together and then the last two terms together.

(12x^3-2x^2)+(18x-3)

We can see that 2x^2 is common in first two terms

And 3 is common in last two terms

Factor them out

(12x^3-2x^2)+(18x-3) = 2x^2(6x-1) + 3(6x-1)

2x^2(6x-1) + 3(6x-1)

Thus option A is correct

6 0
3 years ago
Read 2 more answers
If f(x) = x2 + 1 and g(x) = x – 4, which value is equivalent to (f circle g) (10)?
mariarad [96]

Answer:

jk

Step-by-step explanation:lol

7 0
3 years ago
I dont know how to do this pls help ​
Alecsey [184]

Answer:

1) 225

2) 2304

Step-by-step explanation:

1)

Use geometric mean of legs

x = \sqrt{(16+9)^2 * 9^2} = \sqrt{25^2 * 9^2}  = 25 * 9 = 225

2)

Use geometric mean of altitude

x = \sqrt{(100-36)^2 * 36^2} = \sqrt{64^2 * 36^2} = 64 * 36 = 2304

5 0
3 years ago
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