You must first simplify the radicals by taking out any perfect squares.
√8 + 3√2 + √32 =
√4 * √2 + 3√2 + √16 * √2 =
2√2 + 3√2 + 4√2 =
9√2
Answer:
I got 76 for #1 your welcome
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Answer:</h2>
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Step-by-step explanation:</h2>
For a better understanding of this problem, see the figure below. Our goal is to find 
. Since:
and is a common side both for ΔMRN and ΔMQN, then by SAS postulate, these two triangles are congruent and:
By Pythagorean theorem, for triangle NQP:
Applying Pythagorean theorem again, but for triangle MQN:
Answer:
Top row 2nd one
Step-by-step explanation:
Distrube out .5 first and the equation will be .5x+2
Then add 3 to both sides and you get y=.5x+5
Any number ends with 0, 1, 2, 3, 4, 5, 6, 7, 8 or 9
Given any number. The square of this number is the last digit of square of the original numbers units digit.
For example
23*23 ends with 9 (3*3=9)
149*149 ends with 1 (9*9=81)
2564*2564 ends with 6 (4*4=16)
and so on
so all the possible unit digits of a square number are {0, 1, 4, 5, 6, 9}
because:
0*0= 0 ; 1*1=1; 2*2=4; 3*3=9; 4*4=16; 5*5=25, 6*6=36; 7*7=49; 8*8=64, 9*9=81
Thus, the probability that the square of a number selected from any set of numbers being 7, is 0.
Answer: 0
