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mrs_skeptik [129]

3 years ago

15

What's the answer? Can't figure it out

1 answer:

soldier1979 [14.2K]3 years ago

4 0

9x⁹ - 90x⁸ - 351x⁷

What do each of these numbers have in common?

They ALL have 9x⁷ in them!

So, divide each one of these by 9x⁷

9x⁹ ÷ 9x⁷ = 9x²

-90x⁸ ÷ 9x⁷ = -9x

-351x⁷ ÷ 9x⁷ = -39

So, factorized completely, it is :

9x² - 9x - 39

~Hope I helped!~

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Which values of x satisfy this equation √x^2-10x+25+12√x=15√x

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Answer:

If I am not mistaken, I believe the answers are 1.425 and 17.57, so A and D.

Step-by-step explanation:

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20 points!!<br><br> What are the next three terms of the arithmetic sequence -18, -13, -8, -3,…?

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Each cube in this figure is a -centimeter unit cube. How many cubes are in the prism? [Type your answer as a number.]

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Ilia_Sergeevich [38]

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HELP ME!! im so stumped. will give brainliest!

Olegator [25]

Answer:

$x=1+\sqrt{3}$ and $x=1-\sqrt{3}$

Step-by-step explanation:

We have been given the parabola with vertex (1, -9) and y intercept at (0, -6).

Now we need to find the x-intercepts of that parabola. So first we begin by finding the equation of parabola using vertex formula:

$y=a\left(x-h\right)^2+k$

Vertex for this formula is given by (h,k)

Compare that with given vertex (1,-9), we get: h=1, k=-9

So plug these into vertex formula:

$y=a\left(x-1\right)^2-9$ ...(i)

Plug given point (0, -6). into (i)

$-6=a\left(0-1\right)^2-9$

$-6=a\left(-1\right)^2-9$

$-6=a\left(1\right)-9$

$-6+9=a$

$3=a$

Plug a=3 into (i)

$y=3\left(x-1\right)^2-9$

Now to find x-intercept, we just plug y=0 and solve for x

$y=3\left(x-1\right)^2-9$

$0=3\left(x-1\right)^2-9$

$9=3\left(x-1\right)^2$

$3=\left(x-1\right)^2$

$\pm \sqrt{3}=x-1$

$1+\pm \sqrt{3}=x$

Hence final answer are

$x=1+\sqrt{3}$ and $x=1-\sqrt{3}$

4 0

3 years ago