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elena-14-01-66 [18.8K]
4 years ago
14

Drag the labels to the correct locations. Each label can be used more than once, but not all labels will be used. Let’s look bac

k at the same quadratic functions you saw in the Warm-Up at the beginning of this lesson. Use what you learned about the fundamental theorem of algebra to determine the number of real and complex roots each function has. two distinct real rootsone repeated real rootone real root and one complex roottwo complex roots
Mathematics
1 answer:
inn [45]4 years ago
5 0

Answer:

Graph A: two distinct roots.  Graph B: one repeated real root. Graph C: two complex roots. Graph D: two distinct real roots.

Step-by-step explanation:

Explanation:

Each graph represents a quadratic function. So by the fundamental theorem of algebra, we know that each graph will have two roots.

Graph A crosses the x-axis twice. So, graph A has two distinct real roots.

Graph B touches the x-axis once. A quadratic cannot have one real root and one complex root. So it must have one repeated real root.

Graph C doesn’t cross the x-axis. This means it must have two complex roots.

Graph D crosses the x-axis twice. So, graph D has two distinct real roots.

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14,800 at 6% compounded semiannually for 4 years.. I need to know the interest and the compound amount
Zepler [3.9K]
\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{compounded amount}\\
P=
\begin{array}{llll}
\textit{original amount}\\
\textit{deposited}
\end{array}\to &\$14,800\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, meaning twice}
\end{array}\to &2\\

t=years\to &4
\end{cases}

now, that will give you "A", or the compounded amount

what's the interest earned?  well, subtract the original amount, the Principal, from A, A - P, and you'd be left with the earned interest

--------------------------------------------------------------------------------------------
\bf A=14,800\left(1+\frac{0.06}{2}\right)^{2\cdot  4}

6 0
3 years ago
Determine which of the following terms are not considered to be like terms with the expression -6s ( the two is squared like on
Iteru [2.4K]

Answer:

s^2t^2

4(s\cdot t)

-6(s^2+t)

Step-by-step explanation:

We want to select all the terms that are not considered to be like terms with -6s^2t.

The terms that are like terms with -6s^2t must have s^2t.

It doesn't matter the coefficient.

So we can easily see that all the following are not like terms with -6s^2t:

s^2t^2

4(s\cdot t)

-6(s^2+t)

4 0
3 years ago
Is this true NO LINKS!
mars1129 [50]
FALSE! Ex. If the numbers on the set are 54 and 54 there is no mode (sorry if wrong)
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3 years ago
Find the area of the smaller sector (please help me(​
Evgen [1.6K]

54 cm square.........

7 0
4 years ago
Please solve with answers! thanks.<br> n/5 +0.6=2
Maslowich
N/5 + 0.6=2
We simplify the equation to the form, which is simple to understand n/5 + 0.6=2
We move all terms containing n to the left and all other terms to the right.  + 0.2n=+2-0.6
We simplify left and right side of the equation.  + 0.2n=+1.4
We divide both sides of the equation by 0.2 to get n. n=7
6 0
3 years ago
Read 2 more answers
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