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lina2011 [118]
3 years ago
9

The annual rate of depreciation, x, on a car that was purchased for $9,000 and is worth $4,500 after 5 years can be found using

the following equation: Graph a system of equations to approximate the value of x, the rate of depreciation. Give your answer as a percent. about 4% about 13% about 1.2% cannot be determined

Mathematics
2 answers:
Zolol [24]3 years ago
6 0

Answer:


Step-by-step explanation:

We know that exponential formula of depreciation

A=P(1-x)^t

where

P is the initial amount

x is the interest rate

A is the amount after t years

we are given

The annual rate of depreciation, x, on a car that was purchased for $9,000

so, P=9000

we can plug value it

A=9000(1-x)^t

we are given

when x=5 , A=4500

so, we can plug it and solve for x

4500=9000(1-x)^5

\frac{9000\left(1-x\right)^5}{9000}=\frac{4500}{9000}

\left(1-x\right)^5=\frac{1}{2}

x=-\left(\frac{1}{2}\right)^{\frac{1}{5}}+1

x=0.12945

so, interest rate is 13%

now, we can plug x

and we get

A=9000(1-0.13)^t

A=9000(87)^t


Graph:


mixer [17]3 years ago
6 0

Answer:  --------- 13% -----------




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The element europium (EU) exists in nature as two isotopes: (151 EU)with a mass of 150.9196 amu & (153 EU) with a mass of 15
mixer [17]

Answer:

X = 48.014%

Y = 51.986%

Step-by-step explanation:

Given

151 EU has a mass of 150.9196 amu

153 EU has a mass of 152.9209 amu

Calculating the relative abundance of the two EU isotopes.

First condition that must be satisfied is

X + Y = 100%;

X + Y = 1. ----- Equation 1

Second Condition is;

150.9196X + 152.9209Y = 151.96 ------ Equation 2

In Equation 1; make Y the subject of formula.

So, Y = 1 - X.

Substitute (1 - X) for Y in Equation 2

150.9196X + 152.9209(1 - X) = 151.96 ----Open bracket

150.9196X + 152.9209 - 152.9209X = 151.96 ---- Collect Like Terms

150.9196X - 152.9209X = 151.96 - 152.9209

−2.0013X = -0.9609

X = -0.9609/-2.0013

X = 0.480137910358267

X = 48.014% ----- Approximated

Y = 1 - X

Y = 1 - 48.014%

Y = 0.51986

Y = 51.986% ---- Approximated

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