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Lisa [10]
3 years ago
13

A uniform, solid, 2000.0 kgkg sphere has a radius of 5.00 mm. Find the gravitational force this sphere exerts on a 2.10 kgkg poi

nt mass placed at the following distances from the center of the sphere: (a) 5.04 mm , and (b) 2.70 mm .
Physics
1 answer:
mars1129 [50]3 years ago
6 0

Answer:

0.0110284391534\ N

0.0653784219002\ N

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

m_1 = Mass of sphere = 2000 kg

m_2 = Mass of other sphere = 2.1 kg

r = Distance between spheres

Force of gravity is given by

F=\dfrac{Gm_1m_2}{r^2}\\\Rightarrow F=\dfrac{6.67\times 10^{-11}\times 2000\times 2.1}{(5.04\times 10^{-3})^2}\\\Rightarrow F=0.0110284391534\ N

The gravitational force is 0.0110284391534\ N

F=\dfrac{Gm_1m_2}{r^2}\\\Rightarrow F=\dfrac{6.67\times 10^{-11}\times 2000\times 2.1}{(2.07\times 10^{-3})^2}\\\Rightarrow F=0.0653784219002\ N

The gravitational force is 0.0653784219002\ N

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zlopas [31]

Answer:

Two forces that act in opposite directions produce a resultant force that is smaller than either individual force. To find the resultant force subtract the magnitude of the smaller force from the magnitude of the larger force. The direction of the resultant force is in the same direction as the larger force.

3 0
2 years ago
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An astronaut has a mass of 74.0 kg. 1) how much would the astronaut weigh on mars where surface gravity is 38.0% of that on eart
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274.614N or 61.736lbs
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2 years ago
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2. For each pair of variables, identify which is the independent and which is the dependent variable. a. How much gas is left in
Korvikt [17]

For each pair Independent variable and the dependent variable is -

a. How much gas is left in the gas tank vs. how far the car has traveled.

  • Independent variable =  how far the car has traveled
  • dependent variable = How much gas is left in the gas tank

b. How much money you've spent vs. how much money is in your wallet.

  • Independent variable =  How much money you've spent
  • dependent variable = how much money is in your wallet.

c. How far a toy car traveled vs. how much time went by​

  • Independent variable =  how much time went by​
  • dependent variable = How far a toy car traveled

An independent variable in any experiment or research is a variable that is manipulated or changed in the experiment, this change leads to a direct effect on the dependent variable.

A dependent variable is a variable that is directly affected by the independent variable and it is the variable that is measured or tested in an experiment.

Thus,

a. How much gas is left in the gas tank vs. how far the car has traveled.

  • Independent variable =  how far the car has traveled
  • dependent variable = How much gas is left in the gas tank

b. How much money you've spent vs. how much money is in your wallet.

  • Independent variable =  How much money you've spent
  • dependent variable = how much money is in your wallet.

c. How far a toy car traveled vs. how much time went by​

  • Independent variable =  how much time went by​
  • dependent variable = How far a toy car traveled

Learn more about dependent variables:

brainly.com/question/1670595:

3 0
2 years ago
A mass weighing 14 pounds stretches a spring 2 feet. The mass is attached to a dashpot device that offers a damping force numeri
Elodia [21]

Answer:

The motion is over-damped when λ^2 - w^2 > 0 or when b^{2} > 0.86

The motion is critically when λ^2 - w^2 = 0 or when b^{2} = 0.86

The motion is under-damped when λ^2 - w^2 < 0 or when b^{2} < 0.86

Explanation:

Using the newton second law

k is the spring constante

b positive damping constant

m mass attached

m\frac{d^{2} x}{dt^{2}} = - kx - b\frac{dx}{dt}

x(t) is the displacement from the equilibrium position

\frac{d^{2} x}{dt^{2}} +\frac{b}{m}\frac{dx}{dt} + \frac{k}{m}x = 0

Converting units of weights in units of mass (equation of motion)

m = \frac{W}{g} = \frac{14}{32} = 0.43 slug

From hook's law we can calculate the spring constant k

k = \frac{W}{s} = \frac{14}{2} = 7 lb/ft

If we put m and k into the DE, we get

\frac{d^{2} x}{dt^{2}} +\frac{b}{0.43}\frac{dx}{dt} + 16.28x = 0

Denoting the constants

2λ = \frac{b}{m} = \frac{b}{0.43}

λ = b/0.215

w^{2} = \frac{k}{m} = 16.28

λ^2 - w^2 = \frac{b^{2} }{0.046} - 16.28

This way,

The motion is over-damped when λ^2 - w^2 > 0 or when b^{2} > 0.86

The motion is critically when λ^2 - w^2 = 0 or when b^{2} = 0.86

The motion is under-damped when λ^2 - w^2 < 0 or when b^{2} < 0.86

3 0
3 years ago
Please help me :Find the resultant of two forces of 1.5N and 2.0N at 90 degrees to each other, with the 1.5N force acting vertic
Roman55 [17]

Answer:

resultant force = (f1²+f2²)½

=(1.5²+2²)½

=(2.25+4)½

=(6.25)½

=2.5

Explanation:

okay this question seems easy. now if the 1.5 is vertically upwards so is that 2 is horizontally downwards hence as u say its 90 degrees thn it forms a right angled triangle.

4 0
2 years ago
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