Answer:
S= 1.40x10⁻⁵mol/L
Explanation:
The Henry's Law is given by the next expression:
(1)
<em>where S: is the solubility or concentration of Ar in water, 
: is Henry's law constant and p: is the pressure of the Ar </em>
<u>Since the argon is 0.93%, we need to multiply the equation (1) by this percent:</u>
Therefore, the argon solubility in water is 1.40x10⁻⁵mol/L.
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Answer:
<u><em>note:</em></u>
<u><em>find the attached solution:</em></u>
Answer:
281.25 J
Explanation:
We are told that the two objects with masses m and 3m.
Also that energy stored in the spring is 375 joules.
Now, initially the centre of mass of the system took place at rest, it means v1 = v and v2 = v/3
Thus, from principle of conservation of energy, we have;
½mv² + ½(3m)(v/3)² = 375J
(m + 3m/9)½v² = 375
(4/3)m × ½v² = 375
Multiply both sides by ¾ to get;
½mv² = 375 × ¾
½mv² = 281.25 J
Therefore, energy of lighter body is 281.25 J
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