Answer:
the mass of the cart is 150 kg
Explanation:
given,
mass of boy(m) = 50 kg
speed of boy (v)= 10 m/s
initial velocity of cart (u) = 0
final velocity of cart(V) = 2.5 m/s
mass of the cart(M) = ?
m v + M u = (m + M ) V......................(1)
50× 10 + 0 = (50 + M ) 2.5
M =
M = 150 Kg
hence, the mass of the cart is 150 kg
Answer:
reduce the velocity of collision
Answer:
5.5 km
Explanation:
First, we convert the distance from km/h to m/s
910 * 1000/3600
= 252.78 m/s
Now, we use the formula v²/r = gtanθ to get our needed radius
making r the subject of the formula, we have
r = v²/gtanθ, where
r = radius of curvature needed
g = acceleration due to gravity
θ = angle of banking
r = 252.78² / (9.8 * tan 50)
r = 63897.73 / (9.8 * 1.19)
r = 63897.73 / 11.662
r = 5479 m or 5.5 km
Thus, we conclude that the minimum curvature radius needed for the turn is 5.5 km
Answer:
resultant force = (f1²+f2²)½
=(1.5²+2²)½
=(2.25+4)½
=(6.25)½
=2.5
Explanation:
okay this question seems easy. now if the 1.5 is vertically upwards so is that 2 is horizontally downwards hence as u say its 90 degrees thn it forms a right angled triangle.
